The question asks for the village population two years ago, given the current population and the annual growth rate. This requires reversing the compound growth formula.
An annual increase of 8% means that each year, the population is multiplied by a factor of $1 + 0.08 = 1.08$. To find the population two years ago, we need to divide the current population by this factor twice.
Let the population two years ago be $P$. The population after one year was $P \times (1.08)$. The population after two years (the current population) is $P \times (1.08) \times (1.08) = P \times (1.08)^2$. We are given the current population is 58,320.
Therefore, we need to solve the equation:
$ P \times (1.08)^2 = 58,320 $The population two years ago was 50,000.
Radha saves 25% of her income. If her expenditure increases by 20% and her income increases by 29%, then her savings increase by;
The income of A is 45% more than the income of B and the income of C is 60% less than the sum of the incomes of A and B. The income of D is 20% more than that of C. If the difference between the incomes of B and D is Rs. 13200, then the income (in Rs.) of C is:
The price of cooking oil increased by 25%. Find by how much percentage a family must reduce its consumption in order to maintain the same budget.
The population of a city increased by 30% in the first year and decreased by 15% in the next year. If the present population is 11,050 then population 2 years ago was:
The income of A is 30% less than the income of B and the income of B is 137.5% more than that of C. If the income of A is Rs. 28500 less than that of B, then the income (in Rs.) of C is: