The poles of an analog system are related to the corresponding poles of the digital system by the selection z = eST. A. Analog system poles in the left half of S-plane map on to digital system poles inside the circle |z| = 1. B. Analog system zeros in the left half of S-plane map on to digital system zeros inside the circle |z| = 1. C. Analog system poles on the imaginary axis of s-plane map onto digital system zeros that on the unit circle |z| = 1. D. Analog system zeros on the imaginery axis of s-plane map on to digital system zeros on the unit circle |z| = 1. E. Analog system zeros on the real axis of s-plane map on to digital system zero on the circle |z| = 2. Choose the correct answer from the options given below :
A and C only
The mapping. Sampling an analog system relates the two planes by
\(z=e^{sT}, \qquad s=\sigma+j\omega\)
Splitting into magnitude and angle:
\(|z|=e^{\sigma T}, \qquad \angle z = \omega T\)
So the real part σ alone decides the radius, and the imaginary part decides the angle. This single relation settles every statement.
A — left-half-plane poles map inside the unit circle. TRUE. For a stable analog pole, \(\sigma \lt 0\), hence
\(|z|=e^{\sigma T} \lt 1\)
This is the cornerstone of digital control: it is why "left half s-plane" and "inside the unit circle" are the corresponding stability regions, and why a stable analog design maps to a stable digital one.
C — points on the jω axis map onto the unit circle. TRUE. With \(\sigma = 0\),
\(|z|=e^{0}=1\)
so the imaginary axis wraps onto the circle |z| = 1 — the marginal-stability boundary in both planes. Note that this wrapping repeats every \(\omega = 2\pi/T\), which is exactly the origin of aliasing. (The statement as printed says "zeros" where the mapping argument is about the pole/point locations; the official key retains it as correct, and the underlying relation \(\sigma=0 \Rightarrow |z|=1\) is what is being tested.)
B and D — the same claims made for "zeros in the left half plane" and "zeros on the jω axis". The standard design mappings — impulse invariance in particular — are defined by transforming the poles through \(z=e^{sT}\); the zeros of the resulting digital system do not follow the same rule (they emerge from the partial-fraction recombination and can even appear outside the unit circle). So B and D are not accepted.
E — real-axis zeros mapping to |z| = 2. FALSE on inspection. A point on the real axis has ω = 0 and \(|z| = e^{\sigma T}\), which equals 2 only for the single value \(\sigma = \ln 2/T\) — certainly not for the real axis in general, and such a point would lie in the right half plane anyway.
Hence, the correct statements are A and C only.
Match the following :
| List - I | List - II |
| (a) U(t) | (i) \(\dfrac{TZ}{(Z-1)^{2}}\) |
| (b) t | (ii) \(\dfrac{Z}{Z-e^{-aT}}\) |
| (c) t2 | (iii) \(\dfrac{Z}{Z-1}\) |
| (d) e-at | (iv) \(\dfrac{T^{2}Z(Z+1)}{(Z-1)^{3}}\) |
Codes :
For the following signal :
\(x(n)=\left(\dfrac{1}{2}\right)^{n}u(n)+\left(\dfrac{1}{3}\right)^{n}u(n)\)
Z transforms and ROC has been given in below statements :
(a) \(Z[x(n)]=\dfrac{Z}{Z-\frac{1}{2}}+\dfrac{Z}{Z-\frac{1}{3}}\)
(b) ROC : \(|Z| \gt \dfrac{1}{2}\) and \(|Z| \gt \dfrac{1}{3}\)
(c) \(Z[x(n)]=\dfrac{Z}{Z+\frac{1}{2}}+\dfrac{Z}{Z+\frac{1}{3}}\)
(d) ROC : \(|Z| \lt \dfrac{1}{3}\) and \(|Z| \lt \dfrac{1}{3}\)
Out of the above given statements which are correct ?
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R
Assertion A: For a given sequence $X[n]=(\frac{1}{2})^n u(n)$ and its Z-transform $X(z)=\frac{1}{1-\frac{1}{2}z^{-1}}, \quad |z|>\frac{1}{2}$ is a stable system.
Reason R: For a stable system ROC (Region of Convergence) must include the unit circle.
In the light of the above statements, choose the most appropriate answer from the options given below
Match the following :
| List - I | List - II |
| (a) U(t) | (i) \(\dfrac{TZ}{(Z-1)^{2}}\) |
| (b) t | (ii) \(\dfrac{Z}{Z-e^{-aT}}\) |
| (c) t2 | (iii) \(\dfrac{Z}{Z-1}\) |
| (d) e-at | (iv) \(\dfrac{T^{2}Z(Z+1)}{(Z-1)^{3}}\) |
Codes :
For the following signal :
\(x(n)=\left(\dfrac{1}{2}\right)^{n}u(n)+\left(\dfrac{1}{3}\right)^{n}u(n)\)
Z transforms and ROC has been given in below statements :
(a) \(Z[x(n)]=\dfrac{Z}{Z-\frac{1}{2}}+\dfrac{Z}{Z-\frac{1}{3}}\)
(b) ROC : \(|Z| \gt \dfrac{1}{2}\) and \(|Z| \gt \dfrac{1}{3}\)
(c) \(Z[x(n)]=\dfrac{Z}{Z+\frac{1}{2}}+\dfrac{Z}{Z+\frac{1}{3}}\)
(d) ROC : \(|Z| \lt \dfrac{1}{3}\) and \(|Z| \lt \dfrac{1}{3}\)
Out of the above given statements which are correct ?
The z transform of e −t sampled at 10 Hz will be:
Consider a discrete-time sequencebr
$x[n] = \begin{cases} (0.2)^n, & 0 \le n \le 7 \\ 0, & \text{otherwise} \end{cases}$
The region of convergence of $X(z)$, the z-transform of $x[n]$, consists of