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The z-transform of a causal periodic signal can be determined from the knowledge of the z-transform of its:

The correct answer is

first cycle

Z-Transform of Causal Periodic Signals

The z-transform is a powerful mathematical tool used to analyze discrete-time signals and systems. When dealing with a causal periodic signal, its entire behavior is characterized by its values over a single period or "cycle." Understanding how the z-transform relates to this fundamental cycle is crucial for signal analysis.

Understanding Causal Periodic Signals

  • A signal \(x[n]\) is considered periodic if it repeats itself after a fixed interval. Mathematically, this means there exists a positive integer \(N\) (the fundamental period) such that \(x[n] = x[n+N]\) for all \(n\).
  • A signal is causal if it is zero for all negative time indices, i.e., \(x[n] = 0\) for \(n < 0\).
  • Combining these, a causal periodic signal \(x[n]\) starts at \(n=0\) and repeats its pattern every \(N\) samples.

The Role of the First Cycle

For a causal periodic signal, the sequence of values from \(n=0\) to \(n=N-1\) (inclusive) constitutes its first cycle. Since the signal is periodic and causal, all subsequent cycles are identical copies of this first cycle. Therefore, if we know the values of the signal in its first cycle, we effectively know the entire signal.

Determining the Z-Transform from the First Cycle

Let's consider a causal periodic signal \(x[n]\) with fundamental period \(N\). We can define a finite-duration signal, \(x_p[n]\), which represents the first cycle of \(x[n]\):

\[ x_p[n] = \begin{cases} x[n] & \text{for } 0 \le n \le N-1 \\ 0 & \text{otherwise} \end{cases} \]

The original causal periodic signal \(x[n]\) can be expressed as an infinite sum of shifted versions of its first cycle \(x_p[n]\):

\[ x[n] = x_p[n] + x_p[n-N] + x_p[n-2N] + x_p[n-3N] + \dots \]

This can be written compactly using summation notation:

\[ x[n] = \sum_{k=0}^{\infty} x_p[n-kN] \]

Now, to find the z-transform of \(x[n]\), denoted as \(X(z)\), we apply the z-transform to this summation. Using the linearity property and the time-shifting property of the z-transform \(Z\{x[n-n_0]\} = z^{-n_0} X(z)\):

\[ X(z) = Z\left\{ \sum_{k=0}^{\infty} x_p[n-kN] \right\} \] \[ X(z) = \sum_{k=0}^{\infty} Z\left\{ x_p[n-kN] \right\} \] \[ X(z) = \sum_{k=0}^{\infty} z^{-kN} X_p(z) \] where \(X_p(z)\) is the z-transform of the first cycle \(x_p[n]\).

We can factor out \(X_p(z)\) from the summation:

\[ X(z) = X_p(z) \sum_{k=0}^{\infty} (z^{-N})^k \]

The summation part is a geometric series of the form \(\sum_{k=0}^{\infty} r^k\), which converges to \(\frac{1}{1-r}\) for \(|r| < 1\). In our case, \(r = z^{-N}\).

Therefore, the z-transform of the causal periodic signal \(x[n]\) is:

\[ X(z) = X_p(z) \frac{1}{1-z^{-N}} \quad \text{for } |z^{-N}| < 1 \text{ or } |z| > 1 \]

This formula clearly shows that the z-transform of a causal periodic signal \(X(z)\) can be entirely determined from the knowledge of \(X_p(z)\), which is the z-transform of its first cycle.

Conclusion on Z-Transform Determination

Based on the derivation, the z-transform of a causal periodic signal is directly and uniquely determined by the z-transform of its first cycle. This is because the first cycle contains all the unique information about the signal's pattern, which then repeats infinitely due to periodicity. Other options like "similar cycle," "final cycle," or "reverse cycle" are not the fundamental building blocks from which the entire causal periodic signal is constructed for z-transform analysis. The first cycle is the essential component for this determination.

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Important Questions from Z Transform

  1. The z transform of e −t sampled at 10 Hz will be:

  2. What is the set of all values of z for which X(z) attains a finite value?

  3. The z transform of the following real exponential sequence

    x(n) = {a n ;n >= 0} , {= 0 ; n < 0} and a > 0 is given by

  4. What will be the z-transform of a Unit step function ?

  5. Two discrete-time linear time-invariant systems with impulse responses

    h 1[n] = δ[n - 1] + δ[n + 1] and h 2[n] = δ[n] + δ[n - 1] are connected in cascade, where δ[n] is the Kronecker delta. The impulse response of the cascaded system is

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