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Question

The number 5769116 is divisible by which of the following numbers?

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

4

Given:

Given number: 5769116

Concept used:

1. If the last two digits of a number are divisible by 4, the number is divisible by 4.

2. Divisibility rule for 3 states that a number is completely divisible by 3 if the sum of its digits is divisible by 3.

3. If the last three digits of a number are divisible by 8, then the number is completely divisible by 8.

4. A number is divisible by 5 only if the unit digit is 0 or 5.

5. A number is divisible by 12 when it's simultaneously divisible by 3 and 4.

Calculation:

The sum of digits of 5769116 = 35

Since 35 is not a multiple of 3, 5769116 is not divisible by 3.

According to the concept,

The last two digits of 5769116 are 1 and 6, i.e. 16 which is a multiple of 4.

Hence, 5769116 is divisible by 4.

Apparently, 5769116 is not divisible by 5, 8, and 12.

∴ The number 5769116 is divisible by 4.

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Important Questions from Divisibility and Remainder

  1. If the 8-digit number 888x53y4 is divisible by 72, then what is the value of (7x + 2y), for the maximum value of y?

  2. If all positive divisors of 132 are arranged in descending order, then what digit will be at unit place of first divisor ?

  3. If 3 2019 is divided by 10, then what is the remainder?

  4. The number 3798125P369 is divisible by 7. What is the value of the digit P?

  5. Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.

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    select the correct answer using the code given below:

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