The number 1254216 is divisible by which of the following numbers?
8
The question asks us to determine which of the given numbers (5, 11, 16, or 8) completely divides the number 1254216. To solve this, we will examine the divisibility rules for each of the options and apply them to the number 1254216.
A number is divisible by 5 if its last digit is either 0 or 5.
The number we are checking is 1254216. The last digit is 6.
Since the last digit is 6, and not 0 or 5, the number 1254216 is not divisible by 5.
A number is divisible by 11 if the difference between the sum of its digits at odd places (from the right) and the sum of its digits at even places (from the right) is either 0 or a multiple of 11.
For the number 1254216:
The difference between the sums is \(14 - 7 = 7\).
Since the difference, 7, is neither 0 nor a multiple of 11, the number 1254216 is not divisible by 11.
A number is divisible by 16 if the number formed by its last four digits is divisible by 16. This rule is derived from \(16 = 2^4\).
For the number 1254216, the last four digits form the number 4216.
Now, we check if 4216 is divisible by 16:
Divide 4216 by 16:
\(4216 \div 16\)
We can perform long division or repeated subtraction.
\(4216 = 16 \times 200 + 1016\)
\(1016 = 16 \times 60 + 56\)
\(56 = 16 \times 3 + 8\)
So, \(4216 = 16 \times (200 + 60 + 3) + 8 = 16 \times 263 + 8\).
Since there is a remainder of 8 when 4216 is divided by 16, 4216 is not divisible by 16. Therefore, the number 1254216 is not divisible by 16.
A number is divisible by 8 if the number formed by its last three digits is divisible by 8. This rule is derived from \(8 = 2^3\).
For the number 1254216, the last three digits form the number 216.
Now, we check if 216 is divisible by 8:
Divide 216 by 8:
\(216 \div 8\)
\(216 = 8 \times 27\)
Since 216 is exactly divisible by 8 with no remainder (\(216 \div 8 = 27\)), the number 1254216 is divisible by 8.
Based on our checks using the divisibility rules:
Therefore, among the given options, the number 1254216 is divisible by 8.
| Divisible By | Rule | Example: 1254216 |
|---|---|---|
| 5 | Last digit is 0 or 5. | Last digit is 6. Not divisible by 5. |
| 8 | Last 3 digits form a number divisible by 8. | Last 3 digits are 216. \(216 \div 8 = 27\). Divisible by 8. |
| 11 | Difference of alternate digit sums is 0 or multiple of 11. | \(14 - 7 = 7\). Not divisible by 11. |
| 16 | Last 4 digits form a number divisible by 16. | Last 4 digits are 4216. \(4216 \div 16\) has remainder 8. Not divisible by 16. |
Understanding divisibility rules helps in quickly determining factors of numbers without performing long division. Here are a few more common divisibility rules:
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select the correct answer using the code given below: