The number 2 × 3 × 5 × 7 × 11 + 1 is
a prime number
The question asks us to determine the nature of the number formed by the product of the first five prime numbers plus one. Let's first calculate the value of this number.
The calculation is: \(2 \times 3 \times 5 \times 7 \times 11 + 1\)
Step 1: Calculate the product of the prime numbers:
Step 2: Add 1 to the product:
\(2310 + 1 = 2311\)
So, the number in question is 2311.
Now we need to determine if 2311 is a prime number, a power of a prime, a composite even number, or a composite odd number.
Let's define these terms:
The number 2311 ends with the digit 1. Any integer ending with 1, 3, 5, 7, or 9 is an odd number. Therefore, 2311 is an odd number.
This immediately rules out the possibility of 2311 being a composite even number (Option 3).
To check if 2311 is a power of a prime \(p\), we would see if \(2311 = p^k\) for some prime \(p\) and integer \(k \ge 1\).
Since 2311 is odd, it cannot be a power of 2.
Let's look at small odd prime bases:
While a rigorous proof requires checking for other primes, 2311 does not appear to be a power of a prime number. It is very unlikely for a random number like 2311 to be a power of a prime other than the ones tested, especially considering its magnitude.
To determine if 2311 is prime or composite, we need to check if it has any divisors other than 1 and 2311. We only need to test for prime divisors up to the square root of 2311.
The square root of 2311 is approximately \(\sqrt{2311} \approx 48.07\).
So, we need to test for divisibility by prime numbers less than or equal to 47. These primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47.
Since 2311 is not divisible by any prime number less than or equal to its square root, it means that 2311 has no positive divisors other than 1 and 2311. Therefore, 2311 is a prime number.
Based on our analysis that 2311 is a prime number, let's look at the options:
Thus, the number 2311 is a prime number.
| Property | Value/Status | Conclusion for 2311 |
|---|---|---|
| Calculated Value | \(2311\) | Starting point for analysis |
| Even/Odd | Odd | Not an even number |
| Divisible by Primes < \(\approx 48\) | No (for 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47) | Likely prime |
| Prime/Composite | Prime | Has no factors other than 1 and 2311 |
| Power of a Prime | No | Cannot be expressed as \(p^k\) for prime \(p, k \ge 1\) |
The number \(2 \times 3 \times 5 \times 7 \times 11\) is an example of a primorial, denoted as \(P_k\#\). \(P_k\#\) is the product of the first \(k\) prime numbers. In this case, we calculated \(P_5\# = 2 \times 3 \times 5 \times 7 \times 11 = 2310\).
Numbers of the form \(P_k\# + 1\) are interesting in number theory. Euclid's proof for the infinitude of prime numbers considers a similar construction. If you take a finite list of primes \(\{p_1, p_2, ..., p_k\}\) and consider the number \(N = (p_1 \times p_2 \times ... \times p_k) + 1\), this number \(N\) cannot be divisible by any of the primes \(p_1, p_2, ..., p_k\). This is because dividing \(N\) by any \(p_i\) will always leave a remainder of 1.
Therefore, \(N\) must either be a new prime number itself, or it must be divisible by a prime number not in the original list. This shows there is always a prime larger than any in a finite list, proving that there are infinitely many primes.
Numbers of the form \(P_k\# + 1\) are not always prime. For instance:
The number in our question, 2311, is a prime number of this form.
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