The null hypothesis in ANOVA one-way classification, the study of the variances due to k different sources, is:
H 0 ∶ μ1 = μ 2= ⋯ = μ k
One-way ANOVA compares the means of \(k\) populations using a single classifying factor. The null hypothesis asserts that the factor has no effect on the mean, i.e. all population means are identical:
\[H_{0}:\ \mu_{1}=\mu_{2}=\dots=\mu_{k}\]
The alternative is that at least one pair of means differs. Options involving \(\sigma\) describe assumptions (homoscedasticity), not the null on means; the "at least one pair" form belongs to the alternative hypothesis. Hence Option 1 is correct.
Similar Questions
The prices (in Rs) of different yarns (per kg) in two consecutive years are as follows.
Commodity
Silk
Cotton
Jute
Rayon
Price(in 2016)
600
700
400
300
Price (in 2017)
700
600
480
270
By simple aggregative method, the net price changes in % is:
The 4 th decile for the given data is:
x
f
0
1
1
9
2
26
3
59
4
72
5
52
6
29
7
7
8
1
If the random sample size n is drawn without replacement from a finite population of size N, the correction factor for standard error of sample mean will be:
For the given figures of production of a sugar factory, the estimate of the production for 1976 using straight line trend with origin at the year 1972 by the least squares method (∑x = 0, ∑x 2= 28, ∑xy = 56) is:
Year
Production(‘000 tons) (year)
1969
76
1970
87
1971
95
1972
81
1973
91
1974
96
1975
90
Which of the following methods is NOT used in computation of a seasonal index for time series?
With reference to index numbers, which of the following statements is true?
Marshall-Edgeworth Index number.
By the method of moving averages, the seasonal index for four quarters equals to:
Second differencing in time series can help to eliminate which trend?
(I) Quadratic trend
(II) Linear trend
If Laspeyres price index of a commodity is 208 and Passche's index of the same commodity is 52, the value of Fisher index number will be:
Important Questions from Elementary Statistics
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.
A. 5 and 5
B. 3 and 5
C. 5 and 4
D. 3 and 4
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is
Find the mean of first 5 two-digit multiples of 4.
