The monthly incomes of A and B are in the ration 3 : 5 and the ratio of their savings is 2 : 3 If the income of B is equal to three times the savings of A, then what is the ratio of the expenditures of A and B?
8 : 15
This problem involves working with ratios of income, savings, and expenditures for two individuals, A and B. We are given ratios for their incomes and savings, along with a condition relating the income of B and the savings of A. Our goal is to find the ratio of their expenditures.
The fundamental relationship between income, savings, and expenditure is:
Income = Expenditure + Savings
This can be rearranged to find expenditure:
Expenditure = Income - Savings
Let's represent the incomes and savings using variables based on the given ratios:
So, we have:
We are given that the income of B is equal to three times the savings of A. We can write this as an equation:
Income of B = 3 × Savings of A
Substitute the variable expressions:
$5x = 3 \times (2y)$
$5x = 6y$
Now, we can express one variable in terms of the other. Let's express $y$ in terms of $x$:
$y = \frac{5x}{6}$
Now that we have a relationship between $x$ and $y$, we can express all incomes and savings in terms of a single variable, $x$.
Using the formula Expenditure = Income - Savings, we can calculate the expenditure for both A and B:
Expenditure of A:
Expenditure of A = Income of A - Savings of A
Expenditure of A = $3x - \frac{5x}{3}$
To subtract, find a common denominator (which is 3):
$3x = \frac{9x}{3}$
Expenditure of A = $\frac{9x}{3} - \frac{5x}{3} = \frac{(9-5)x}{3} = \frac{4x}{3}$
Expenditure of B:
Expenditure of B = Income of B - Savings of B
Expenditure of B = $5x - \frac{5x}{2}$
To subtract, find a common denominator (which is 2):
$5x = \frac{10x}{2}$
Expenditure of B = $\frac{10x}{2} - \frac{5x}{2} = \frac{(10-5)x}{2} = \frac{5x}{2}$
Now we need to find the ratio of the expenditures of A and B, which is $\frac{\text{Expenditure of A}}{\text{Expenditure of B}}$.
Ratio of Expenditures = $\frac{\frac{4x}{3}}{\frac{5x}{2}}$
To divide fractions, multiply the numerator fraction by the reciprocal of the denominator fraction:
Ratio of Expenditures = $\frac{4x}{3} \times \frac{2}{5x}$
Cancel out the $x$ term (since $x$ is a common positive constant, it's not zero):
Ratio of Expenditures = $\frac{4}{3} \times \frac{2}{5} = \frac{4 \times 2}{3 \times 5} = \frac{8}{15}$
So, the ratio of the expenditures of A and B is 8 : 15.
Let's summarize the calculated values in a table for clarity:
| A | B | |
|---|---|---|
| Income | $3x$ | $5x$ |
| Savings | $\frac{5x}{3}$ | $\frac{5x}{2}$ |
| Expenditure | $\frac{4x}{3}$ | $\frac{5x}{2}$ |
The ratio of Expenditures A : B is $\frac{4x}{3} : \frac{5x}{2}$.
To express this ratio with integers, we can multiply both parts by the least common multiple (LCM) of the denominators (3 and 2), which is 6.
Ratio = $\left(\frac{4x}{3} \times 6\right) : \left(\frac{5x}{2} \times 6\right)$
Ratio = $(4x \times 2) : (5x \times 3)$
Ratio = $8x : 15x$
Ratio = $8 : 15$
The ratio of the expenditures of A and B is 8 : 15.
Here's a quick recap of the key values and steps involved in solving this ratio problem:
| Concept | Ratio (A : B) | Variable Expressions | Calculated Values (in terms of x) |
|---|---|---|---|
| Income | 3 : 5 | $3x, 5x$ | $3x, 5x$ |
| Savings | 2 : 3 | $2y, 3y$ | $\frac{5x}{3}, \frac{5x}{2}$ (using $y = 5x/6$) |
| Expenditure | ? | Income - Savings | $\frac{4x}{3}, \frac{5x}{2}$ |
| Expenditure Ratio | Calculated | $\frac{4x/3}{5x/2}$ | 8 : 15 |
Ratio and proportion problems are common in quantitative aptitude tests. Understanding the relationship between different quantities, like income, savings, and expenditure, is crucial. Here are some related concepts:
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