A sum of Rs. 15525 is divided among Sunil, Anil and Jamil such that if Rs. 22, Rs. 35 and Rs. 48 be diminished from their shares respectively, their remaining sums shall be in the ratio 7 : 10 : 13. What would have been the ratio of their sums if Rs. 16, Rs. 77 and Rs. 37 respectively were added to their original shares?
36 : 52 : 67
The problem involves dividing a total sum of Rs. 15525 among three people: Sunil, Anil, and Jamil. We are given two conditions related to their shares:
Let's denote the original shares of Sunil, Anil, and Jamil as S, A, and J respectively. The total sum is Rs. 15525.
So, we know that \(S + A + J = 15525\).
According to the first condition, if Rs. 22 is diminished from Sunil's share, Rs. 35 from Anil's, and Rs. 48 from Jamil's, their remaining sums are in the ratio 7 : 10 : 13.
This can be written as:
\((S - 22) : (A - 35) : (J - 48) = 7 : 10 : 13\)
We can represent these remaining amounts using a common multiple, say \(k\):
From these equations, we can express the original shares S, A, and J in terms of \(k\):
Now, we use the total sum \(S + A + J = 15525\) to find the value of \(k\).
\((7k + 22) + (10k + 35) + (13k + 48) = 15525\)
Combine the terms with \(k\) and the constant terms:
\((7k + 10k + 13k) + (22 + 35 + 48) = 15525\)
\(30k + 105 = 15525\)
Subtract 105 from both sides:
\(30k = 15525 - 105\)
\(30k = 15420\)
Divide by 30 to find \(k\):
\(k = \frac{15420}{30}\)
\(k = 514\)
Now that we have the value of \(k\), we can calculate the original shares:
Let's quickly verify the total sum: \(3620 + 5175 + 6730 = 15525\). This matches the given total sum.
The second part of the question asks for the ratio of their sums if Rs. 16, Rs. 77, and Rs. 37 were added to their original shares respectively.
The ratio of their new sums is \(3636 : 5252 : 6767\).
To simplify this ratio, we need to find the greatest common divisor (GCD) of these three numbers. Let's try dividing by small numbers or looking at the options to see if there's a common factor related to them.
Let's check if 101 is a common factor (often used in such problems):
Since 101 divides all three numbers perfectly, the simplified ratio is \(36 : 52 : 67\).
The ratio of their sums if Rs. 16, Rs. 77, and Rs. 37 were added to their original shares is 36 : 52 : 67.
| Item | Value/Expression |
|---|---|
| Total Sum | Rs. 15525 |
| Original Shares | S, A, J |
| Condition 1 Ratio | (S-22) : (A-35) : (J-48) = 7 : 10 : 13 |
| Common Multiple (k) | 514 |
| Sunil's Original Share (S) | Rs. 3620 |
| Anil's Original Share (A) | Rs. 5175 |
| Jamil's Original Share (J) | Rs. 6730 |
| Sunil's New Share (S+16) | Rs. 3636 |
| Anil's New Share (A+77) | Rs. 5252 |
| Jamil's New Share (J+37) | Rs. 6767 |
| New Ratio | 3636 : 5252 : 6767 = 36 : 52 : 67 |
| Concept | Description | Example |
|---|---|---|
| Ratio | Comparison of two or more quantities of the same kind, expressed as a:b. | If A has 10 apples and B has 20, ratio A:B is 10:20 = 1:2. |
| Proportion | Equality of two ratios. If a:b = c:d, then ad = bc. | 2:3 = 4:6 is a proportion because 2x6 = 3x4 = 12. |
| Dividing a Sum in Ratio | To divide a sum P in the ratio a:b:c, the parts are \(\frac{a}{a+b+c} \times P\), \(\frac{b}{a+b+c} \times P\), \(\frac{c}{a+b+c} \times P\). | Divide 100 in 2:3:5. Parts are \(\frac{2}{10}\times 100=20\), \(\frac{3}{10}\times 100=30\), \(\frac{5}{10}\times 100=50\). |
| Solving Ratio Problems | Often involves setting up equations using a common multiple (like 'k') or proportions based on the given ratios and total amounts. | If A:B = 2:3, A=2k, B=3k. If total is 100, 2k+3k=100, 5k=100, k=20. A=40, B=60. |
Ratio problems involving sums of money or quantities can often be effectively solved using algebraic methods. By representing the unknown quantities (like shares) using variables and incorporating a common factor (like \(k\)), we can translate the word problem into equations.
Steps typically involved:
This systematic approach helps break down complex ratio and proportion problems into manageable steps.
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