The matrix is \(\left[ {\begin{array}{c} 0&{ - 4 + i}\\ {4 + i}&0 \end{array}} \right]\)
Skew-Hermitian
The question asks us to classify the given matrix:
\( A = \left[ {\begin{array}{c} 0&{ - 4 + i}\\ {4 + i}&0 \end{array}} \right] \)
We need to determine if this matrix is symmetric, skew-symmetric, Hermitian, or Skew-Hermitian. Since the matrix contains complex numbers (the imaginary unit \(i\)), we should pay close attention to the definitions involving complex conjugates.
Let's define the relevant properties for complex matrices:
For matrices with complex entries, the concepts of Hermitian and Skew-Hermitian are more fundamental than symmetric and skew-symmetric, as they involve conjugation which is crucial for complex numbers.
Let's calculate the transpose and conjugate transpose of the given matrix \(A\).
The given matrix is:
\( A = \left[ {\begin{array}{c} 0&{ - 4 + i}\\ {4 + i}&0 \end{array}} \right] \)
To find the transpose, we swap rows and columns:
\( A^T = \left[ {\begin{array}{c} 0&{4 + i}\\ { - 4 + i}&0 \end{array}} \right] \)
Comparing \(A^T\) with \(A\), we see they are not equal. \(A^T \ne A\). Also, \(A^T \ne -A\). So, the matrix is neither symmetric nor skew-symmetric in the standard sense applied to complex matrices.
To find the complex conjugate, we replace each element \(a_{jk}\) with its complex conjugate \(\overline{a_{jk}}\). Recall that for a complex number \(z = x + iy\), its conjugate is \(\overline{z} = x - iy\).
So, the complex conjugate matrix \(A^*\) is:
\( A^* = \left[ {\begin{array}{c} \overline{0}&{\overline{- 4 + i}}\\ {\overline{4 + i}}&{\overline{0}} \end{array}} \right] = \left[ {\begin{array}{c} 0&{- 4 - i}\\ {4 - i}&0 \end{array}} \right] \)
To find the conjugate transpose \(A^\dagger\), we take the transpose of \(A^*\):
\( A^\dagger = (A^*)^T = \left[ {\begin{array}{c} 0&{4 - i}\\ {- 4 - i}&0 \end{array}} \right] \)
A matrix \(A\) is Hermitian if \(A^\dagger = A\).
We have \(A^\dagger = \left[ {\begin{array}{c} 0&{4 - i}\\ {- 4 - i}&0 \end{array}} \right]\) and \(A = \left[ {\begin{array}{c} 0&{ - 4 + i}\\ {4 + i}&0 \end{array}} \right]\).
Clearly, \(A^\dagger \ne A\). So, the matrix is not Hermitian.
A matrix \(A\) is Skew-Hermitian if \(A^\dagger = -A\).
Let's calculate \(-A\):
\( -A = -1 \times \left[ {\begin{array}{c} 0&{ - 4 + i}\\ {4 + i}&0 \end{array}} \right] = \left[ {\begin{array}{c} -1 \times 0&{-1 \times (- 4 + i)}\\ {-1 \times (4 + i)}&{-1 \times 0} \end{array}} \right] = \left[ {\begin{array}{c} 0&{4 - i}\\ {- 4 - i}&0 \end{array}} \right] \)
Now, let's compare \(A^\dagger\) and \(-A\):
\( A^\dagger = \left[ {\begin{array}{c} 0&{4 - i}\\ {- 4 - i}&0 \end{array}} \right] \)
\( -A = \left[ {\begin{array}{c} 0&{4 - i}\\ {- 4 - i}&0 \end{array}} \right] \)
We see that \(A^\dagger = -A\).
Therefore, the given matrix is a Skew-Hermitian matrix.
Based on our calculations, the given matrix satisfies the condition \(A^\dagger = -A\). This is the definition of a Skew-Hermitian matrix.
| Property | Condition | Applies to (Generally) |
|---|---|---|
| Symmetric | \(A^T = A\) | Real matrices |
| Skew-Symmetric | \(A^T = -A\) | Real matrices |
| Hermitian | \(A^\dagger = A\) | Complex matrices |
| Skew-Hermitian | \(A^\dagger = -A\) | Complex matrices |
When dealing with matrices containing complex numbers, the concepts of Hermitian and Skew-Hermitian are generalizations of symmetric and skew-symmetric matrices from the real case. For a real matrix (where all entries are real numbers), the complex conjugate of any element is just the element itself (\(\overline{a_{jk}} = a_{jk}\)). In this case, \(A^* = A\), and thus \(A^\dagger = (A^*)^T = A^T\).
This shows that Hermitian and Skew-Hermitian matrices are the appropriate classifications when complex entries are involved, encompassing the real symmetric and skew-symmetric cases as special instances.
If \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} 1&1&{ - 1}\\ 2&{ - 3}&4\\ 3&{ - 2}&3 \end{array}} \right]{\rm{\;and\;\;B}} = \left[ {\begin{array}{*{20}{c}} { - 1}&{ - 2}&{ - 1}\\ 6&{12}&6\\ 5&{10}&5 \end{array}} \right]\) then which of the following is/are correct?
1. A and B commute.
2. AB is a null matrix.
Select the correct answer using the code given below:Which one of the following matrices is an elementary matrix?
How many distinct matrices exist with all four entries taken from (1, 2)?
If A and B are square matrices of order 2 such that det(AB) = det(BA), then which one of the following is correct?
If matrix \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} {1 - {\rm{i}}}&{\rm{i}}\\ { - {\rm{i}}}&{1 - {\rm{i}}} \end{array}} \right]\) where \(\rm i = \sqrt {-1},\) then which one of the following is correct?