Let \(A = \left[ {\begin{array}{*{20}{c}} 1&1&3\\ 5&2&6\\ { - 2}&{ - 1}&{ - 3} \end{array}} \right]\), then A is
None of these
The question asks us to classify the given matrix \(A = \left[ {\begin{array}{*{20}{c}} 1&1&3\\ 5&2&6\\ { - 2}&{ - 1}&{ - 3} \end{array}} \right]\) based on specific matrix properties: Nilpotent, Idempotent, and Scalar. We need to check if this matrix A fits any of these definitions.
Let's quickly define the matrix types mentioned in the options:
The given matrix A is: \(A = \left[ {\begin{array}{*{20}{c}} 1&1&3\\ 5&2&6\\ { - 2}&{ - 1}&{ - 3} \end{array}} \right]\) A Scalar matrix must be a diagonal matrix, meaning all its non-diagonal elements must be zero. Looking at matrix A, we see elements like \(A_{12} = 1\), \(A_{21} = 5\), etc., which are not zero. Therefore, matrix A is not a Scalar matrix.
To check if matrix A is Idempotent or Nilpotent (specifically if \(A^2 = 0\)), we must calculate the product of matrix A with itself, i.e., \(A^2 = A \times A\).
Let's perform the matrix multiplication:
\(A^2 = \left[ {\begin{array}{*{20}{c}} 1&1&3\\ 5&2&6\\ { - 2}&{ - 1}&{ - 3} \end{array}} \right] \left[ {\begin{array}{*{20}{c}} 1&1&3\\ 5&2&6\\ { - 2}&{ - 1}&{ - 3} \end{array}} \right]\)
We calculate each element of the resulting \(3 \times 3\) matrix:
So, the matrix \(A^2\) is:
| 0 | 0 | 0 |
| 3 | 3 | 9 |
| -1 | -1 | -3 |
We found that \(A^2 = \left[ {\begin{array}{*{20}{c}} 0&0&0\\ 3&3&9\\ { - 1}&{ - 1}&{ - 3} \end{array}} \right]\). This is not the zero matrix, so matrix A is not Nilpotent with an index of 2. We also compare \(A^2\) with the original matrix A. Since \(A^2 \neq A\), matrix A is not Idempotent.
Based on our analysis, the given matrix A does not satisfy the conditions for being a Nilpotent matrix (with index 2), an Idempotent matrix, or a Scalar matrix.
Since matrix A does not fit the definitions of Nilpotent, Idempotent, or Scalar matrices, the correct classification among the given options is "None of these".
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