If A = \(\left[ {\begin{array}{*{20}{c}} 1&{3 + x}&2\\ {1 - x}&2&{y + 1}\\ 2&{5 - y}&3 \end{array}} \right]\) is a symmetric matrix, then 3x + y is equal to?
-1
A symmetric matrix is a square matrix that is equal to its transpose. In simpler terms, if A is a symmetric matrix, then \(A = A^T\). This property means that the element in the i-th row and j-th column is equal to the element in the j-th row and i-th column for all i and j. Mathematically, this is expressed as \(a_{ij} = a_{ji}\) for all \(i, j\).
The given matrix is:
\( A = \left[ {\begin{array}{*{20}{c}} 1&{3 + x}&2\\ {1 - x}&2&{y + 1}\\ 2&{5 - y}&3 \end{array}} \right] \)
For this matrix A to be a symmetric matrix, the elements must satisfy the condition \(a_{ij} = a_{ji}\).
We need to compare the off-diagonal elements of the matrix A based on the property of a symmetric matrix:
Let's write down the equations based on the elements of matrix A:
Now, we solve the equations we obtained:
Equation 1: \(3 + x = 1 - x\)
Add x to both sides:
\(3 + x + x = 1 - x + x\)
\(3 + 2x = 1\)
Subtract 3 from both sides:
\(2x = 1 - 3\)
\(2x = -2\)
Divide by 2:
\(x = \frac{-2}{2}\)
\(x = -1\)
Equation 2: \(y + 1 = 5 - y\)
Add y to both sides:
\(y + 1 + y = 5 - y + y\)
\(2y + 1 = 5\)
Subtract 1 from both sides:
\(2y = 5 - 1\)
\(2y = 4\)
Divide by 2:
\(y = \frac{4}{2}\)
\(y = 2\)
So, we found the values of x and y are \(x = -1\) and \(y = 2\). This uses the concept of a symmetric matrix.
The question asks for the value of \(3x + y\). We substitute the values of x and y we just found:
\(3x + y = 3(-1) + 2\)
Perform the multiplication:
\(3(-1) = -3\)
Now add 2:
\(-3 + 2 = -1\)
Thus, the value of \(3x + y\) is -1.
This calculation confirms how the definition of a symmetric matrix helps determine the unknown elements and solve related expressions.
Based on the properties of a symmetric matrix, we found \(x = -1\) and \(y = 2\). Using these values, \(3x + y = -1\).
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