To find the true bearing of the line, we need to adjust the given magnetic bearing by considering both the magnetic declination and the local attraction. Let's work through the steps to determine the true bearing:
- Identify the given values:
- The magnetic bearing of the line = 182°
- Magnetic declination = 3° E (East means the magnetic north is east of true north, so we add this to the magnetic bearing)
- Local attraction correction = -1° (a negative sign indicates we need to subtract this from the adjusted bearing)
- Calculate the Adjusted Magnetic Bearing:
- Add the magnetic declination to the magnetic bearing: 182° + 3° = 185°
- Apply the Local Attraction Correction:
- Subtract the local attraction correction: 185° - 1° = 184°
- Thus, the true bearing of the line is 184°.
The correct option is:
- 184°
Hence, the true bearing of the line is indeed 184° after applying all necessary corrections. The other options can be ruled out because they do not account for both the magnetic declination and the local attraction in the manner described above.
Important Questions from Traversing
- The forebearing of four sides of a closed quadrilateral ABCDA are
AB = 60°, BC = 149.87°, CD = 269.5°, DA = 20.17°.
The calculated value of interior angle D is _____° (Answer in decimal degrees and rounded off to two decimal values). The angular misclosure of the closed-loop traverse shown in the figure is _____________ ° (Answer in decimal degrees and rounded off to three decimal places)
- It is needed to establish the coordinates of a station A. Two stations B and C are available whose coordinates are given in the table.
Length of line CA = 1212.38 m; ∠BCA = 64°.
The Easting of station A is _______ m (Rounded off to two decimal places).
Assume station A lies to the west of the traverse line BC.Station Easting (m) Northing (m) B 11054.09 9484.37 C 10827.62 10112.15 - If the departure and latitude of a line are 70 m and -130 m, respectively, then the whole circle bearing of the line in degrees is
While carrying out a traverse survey ABCDA' using a theodolite with the originating station A, the departures and latitudes of the lines, as obtained, are shown in the following figure (not drawn to scale). It is seen that, due to the observational errors, the originating station A and its computed station A' are not the same. For this survey, the 'closing error' in m is
