The angular misclosure of the closed-loop traverse shown in the figure is _____________ ° (Answer in decimal degrees and rounded off to three decimal places)
Step 1: Concept
For a closed traverse with $n$ sides, the theoretical sum of interior angles is:
$ (n-2)\times 180^\circ $
Here, number of sides $n = 6$
So, theoretical sum:
$ (6-2)\times 180 = 720^\circ $
Step 2: Given angles
$66^\circ 40' 30''$
$132^\circ 45' 30''$
$227^\circ 26' 15''$
$64^\circ 00' 00''$
$97^\circ 35' 45''$
$131^\circ 35' 00''$
Step 3: Convert to decimal degrees
$66^\circ 40' 30'' = 66 + \frac{40}{60} + \frac{30}{3600} = 66.675^\circ$
$132^\circ 45' 30'' = 132.758^\circ$
$227^\circ 26' 15'' = 227.438^\circ$
$64^\circ 00' 00'' = 64.000^\circ$
$97^\circ 35' 45'' = 97.596^\circ$
$131^\circ 35' 00'' = 131.583^\circ$
Step 4: Sum of given angles
Total =
$66.675 + 132.758 + 227.438 + 64 + 97.596 + 131.583 = 720.050^\circ$
Step 5: Angular misclosure
$ \text{Misclosure} = |\text{Observed} - \text{Theoretical}| $
$ = |720.050 - 720| = 0.050^\circ $
Final Answer:
$\boxed{0.050^\circ}$
| Station | Easting (m) | Northing (m) |
|---|---|---|
| B | 11054.09 | 9484.37 |
| C | 10827.62 | 10112.15 |
While carrying out a traverse survey ABCDA' using a theodolite with the originating station A, the departures and latitudes of the lines, as obtained, are shown in the following figure (not drawn to scale). It is seen that, due to the observational errors, the originating station A and its computed station A' are not the same. For this survey, the 'closing error' in m is

Figure below shows an open traverse PQRS, where P is the starting point of traverse and S is the end point of traverse. Which one of the following is correct?