Lifetime (days) 0-10 10-20 20-30 30-40 40-50 50-60 Frequency 10 35 52 61 38 29
The question asks us to calculate the modal lifetime from the given frequency distribution table. The modal lifetime represents the most frequent lifetime range in the data.
First, we need to identify the modal class, which is the class interval with the highest frequency.
| Lifetime (days) | Frequency |
|---|---|
| 0-10 | 10 |
| 10-20 | 35 |
| 20-30 | 52 |
| 30-40 | 61 |
| 40-50 | 38 |
| 50-60 | 29 |
From the table, the highest frequency is 61, which corresponds to the lifetime interval 30-40 days. Therefore, the modal class is 30-40.
We use the formula for calculating the mode of grouped data:
Mode = \(l + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h\)
Where:
From the identified modal class (30-40):
Substitute these values into the formula:
Mode = \(30 + \frac{61 - 52}{2 \times 61 - 52 - 38} \times 10\)
Mode = \(30 + \frac{9}{122 - 52 - 38} \times 10\)
Mode = \(30 + \frac{9}{122 - 90} \times 10\)
Mode = \(30 + \frac{9}{32} \times 10\)
Mode = \(30 + \frac{90}{32}\)
Mode = \(30 + 2.8125\)
Mode = \(32.8125\)
The question requires the answer to be rounded up to one decimal place. Rounding 32.8125 gives 32.8.
Therefore, the modal lifetime is approximately 32.8 days.
Find the median of the data 11, 16, 33, 15, 51, 19, 71, 75, 21, 17.
For a data, if the mean is 28.5 and the median is 32, then the mode using empirical formula is:
| Marks | Number of Students |
|---|---|
| 20 - 30 | 5 |
| 30 - 40 | 12 |
| 40 - 50 | 10 |
| 50 - 60 | 15 |
| 60 - 70 | 8 |
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
What will be the difference between mean and median of the given data?
21, 11, 27, 8, 5, 12, 7, 23, 3, 14, 9, 19Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.
A. 5 and 5
B. 3 and 5
C. 5 and 4
D. 3 and 4
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is