Marks Number of Students 20 - 30 5 30 - 40 12 40 - 50 10 50 - 60 15 60 - 70 8
To find the mean marks obtained by the students, we need to calculate the mean of the grouped frequency distribution.
| Marks Interval | Number of Students (\(f_i\)) | Midpoint (\(x_i\)) | \(f_i x_i\) |
| 20 - 30 | 5 | \(\frac{20+30}{2} = 25\) | \(5 \times 25 = 125\) |
| 30 - 40 | 12 | \(\frac{30+40}{2} = 35\) | \(12 \times 35 = 420\) |
| 40 - 50 | 10 | \(\frac{40+50}{2} = 45\) | \(10 \times 45 = 450\) |
| 50 - 60 | 15 | \(\frac{50+60}{2} = 55\) | \(15 \times 55 = 825\) |
| 60 - 70 | 8 | \(\frac{60+70}{2} = 65\) | \(8 \times 65 = 520\) |
| Total | \(N = 50\) | \(\sum f_i x_i = 2340\) |
Using the sums calculated:
Mean = \(\frac{\sum f_i x_i}{N} = \frac{2340}{50}\)
Mean = \(46.8\)
The mean marks obtained by students is 46.8.
Find the median of the data 11, 16, 33, 15, 51, 19, 71, 75, 21, 17.
For a data, if the mean is 28.5 and the median is 32, then the mode using empirical formula is:
| Lifetime (days) | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
| Frequency | 10 | 35 | 52 | 61 | 38 | 29 |
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
What will be the difference between mean and median of the given data?
21, 11, 27, 8, 5, 12, 7, 23, 3, 14, 9, 19Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.
A. 5 and 5
B. 3 and 5
C. 5 and 4
D. 3 and 4
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is