Marks Number of Students 20 - 30 5 30 - 40 12 40 - 50 10 50 - 60 15 60 - 70 8
To find the mean marks obtained by the students, we need to calculate the mean of the grouped frequency distribution.
| Marks Interval | Number of Students (\(f_i\)) | Midpoint (\(x_i\)) | \(f_i x_i\) |
| 20 - 30 | 5 | \(\frac{20+30}{2} = 25\) | \(5 \times 25 = 125\) |
| 30 - 40 | 12 | \(\frac{30+40}{2} = 35\) | \(12 \times 35 = 420\) |
| 40 - 50 | 10 | \(\frac{40+50}{2} = 45\) | \(10 \times 45 = 450\) |
| 50 - 60 | 15 | \(\frac{50+60}{2} = 55\) | \(15 \times 55 = 825\) |
| 60 - 70 | 8 | \(\frac{60+70}{2} = 65\) | \(8 \times 65 = 520\) |
| Total | \(N = 50\) | \(\sum f_i x_i = 2340\) |
Using the sums calculated:
Mean = \(\frac{\sum f_i x_i}{N} = \frac{2340}{50}\)
Mean = \(46.8\)
The mean marks obtained by students is 46.8.
What is the mode of the given data?
3, 0, 1, 0, 2, 1, 2, 0, 1, 2, 1, 1, 1, 3, 2What is the mode of the given data?
21, 22, 23, 23, 24, 21, 22, 23, 21, 23, 24, 23, 21, 23A bowler has taken 0, 3, 2, 1, 5, 3, 4, 5, 5, 2, 2, 0, 0, 1 and 2 wickets in 15 consecutive matches. What is the mode of the given data?
The data given below shows the number of people who have saved a certain amount of money.
Saving (In Rs.) | Number of people |
5 | 1 |
15 | 3 |
20 | 4 |
25 | 2 |
30 | 1 |
35 | 1 |
40 | 2 |
What is the median of the given data?
If the ratio of mean and median of a certain data is 4 : 5, then find the ratio of its mean and mode.