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Question

The first four moments about the mean of distribution are 0, μ 2, 0.7 and 18.75. If the distribution is mesokurtic, the value of μ 2, is

The correct answer is

2.5

Understanding Moments About the Mean and Kurtosis

Moments about the mean are important measures used in statistics to describe the characteristics of a distribution. The first moment about the mean ($\mu_1$) is always 0. The second moment about the mean ($\mu_2$) is the variance. The third moment ($\mu_3$) measures skewness, and the fourth moment ($\mu_4$) measures kurtosis.

Kurtosis measures the "tailedness" of a distribution's probability distribution. It indicates how peaked or flat a distribution is relative to a normal distribution. The coefficient of kurtosis, denoted by $\beta_2$, is calculated using the fourth and second moments about the mean:

$\beta_2 = \frac{\mu_4}{\mu_2^2}$

Based on the value of $\beta_2$, distributions are classified as:

  • Mesokurtic: $\beta_2 = 3$ (like a normal distribution)
  • Leptokurtic: $\beta_2 > 3$ (more peaked, fatter tails than normal)
  • Platykurtic: $\beta_2 < 3$ (less peaked, thinner tails than normal)

Calculating the Second Moment (\(\mu_2\)) for a Mesokurtic Distribution

We are given the first four moments about the mean of a distribution:

  • First moment, $\mu_1 = 0$ (as expected for moments about the mean)
  • Second moment, $\mu_2 = \mu_2$ (this is what we need to find)
  • Third moment, $\mu_3 = 0.7$
  • Fourth moment, $\mu_4 = 18.75$

We are also told that the distribution is mesokurtic. For a mesokurtic distribution, the coefficient of kurtosis, $\beta_2$, is equal to 3.

Using the formula for $\beta_2$:

$\beta_2 = \frac{\mu_4}{\mu_2^2}$

Since the distribution is mesokurtic, we set $\beta_2 = 3$:

$3 = \frac{\mu_4}{\mu_2^2}$

Now, we substitute the given value of the fourth moment, $\mu_4 = 18.75$:

$3 = \frac{18.75}{\mu_2^2}$

To solve for $\mu_2^2$, we can rearrange the equation:

$\mu_2^2 = \frac{18.75}{3}$

Performing the division:

$\mu_2^2 = 6.25$

Finally, to find $\mu_2$, we take the square root of 6.25. Since the second moment about the mean represents variance, it must be a non-negative value.

$\mu_2 = \sqrt{6.25}$

$\mu_2 = 2.5$

Therefore, the value of $\mu_2$ for this mesokurtic distribution is 2.5.

Revision Table: Moments and Kurtosis Concepts

Concept Description Formula / Value
First Moment (\(\mu_1\)) Mean deviation 0 (about the mean)
Second Moment (\(\mu_2\)) Variance $\sigma^2$
Third Moment (\(\mu_3\)) Skewness measure $\mu_3$
Fourth Moment (\(\mu_4\)) Kurtosis measure $\mu_4$
Kurtosis Coefficient (\(\beta_2\)) Measures tailedness/peakedness $\beta_2 = \frac{\mu_4}{\mu_2^2}$
Mesokurtic Distribution Similar kurtosis to normal distribution $\beta_2 = 3$

Additional Information on Distribution Shape

Kurtosis helps us understand the shape of a distribution, particularly concerning its tails and peak.

  • Leptokurtic: These distributions have fatter tails and a sharper peak than a normal distribution ($\beta_2 > 3$). This indicates a higher probability of extreme values (outliers).
  • Platykurtic: These distributions have thinner tails and a flatter peak than a normal distribution ($\beta_2 < 3$). This indicates a lower probability of extreme values.

Understanding these moments and kurtosis allows for a more complete description of a dataset's characteristics beyond just its mean and standard deviation.

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Important Questions from Basics of Probability

  1. If the data are skewed, which option of central tendency measure is the most unreliable indicator?

  2. In a negatively skewed distribution

  3. If the distribution is negatively skewed, then the:

  4. If Mean > Median > Mode, the distribution is:

  5. The following measures were computed for a moderately symmetrical frequency distribution: mean = 50, coefficient of variation = 35% and Karl Pearson's Coefficient of Skewness = - 0.25. The value of the median of the distribution is:

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