The particle's energy ($E$) and wavevector ($k$) are related by the dispersion relation $E = Ck$ in two dimensions, where $C$ is a constant.
The density of states $D(E)$ is defined as the number of states per unit energy interval. It can be calculated from the total number of states $N(E)$ with energy less than or equal to $E$ using the formula $D(E) = \frac{dN}{dE}$.
In a 2D system, the number of available states $N$ is proportional to the area in k-space. The area is given by $\pi k^2$, where $k$ is the magnitude of the wavevector.
From the dispersion relation $E = Ck$, we can express $k$ in terms of $E$: $k = \frac{E}{C}$
Substituting this into the expression for the area in k-space:
Area $\propto (\frac{E}{C})^2 = \frac{E^2}{C^2}$
Since the number of states $N(E)$ is proportional to this area:
N(E) \propto \frac{E^2}{C^2}
Thus, $N(E)$ is proportional to $E^2$.
Now, we find the density of states $D(E)$ by differentiating $N(E)$ with respect to $E$:
$D(E) = \frac{dN}{dE} \propto \frac{d(E^2)}{dE}$
$D(E) \propto 2E$
This shows that $D(E)$ is proportional to $E^1$.
The problem states that the density of states $D(E)$ is proportional to $E^p$, i.e., $D(E) \propto E^p$. Comparing this with our result $D(E) \propto E^1$, we find:
p = 1
The value of $p$ is 1.
Crystal structures of two metals A and B are two-dimensional square lattices with same lattice constant $a$. Electrons in metals behave as free electrons. The Fermi surfaces corresponding to A and B are shown by solid circles in figures. 
The electron concentrations in A and B are $n_A$ and $n_B$, respectively. The value of $(\frac{n_B}{n_A})$ is
If $X$ is the dimensionality of a free electron gas, the energy ($E$) dependence of density of states is given by $E^{½X-Y}$, where $Y$ is ________.