$-\frac{2}{3}$
To solve this problem, we need to analyze the energy levels in a system obeying the free electron model at absolute zero temperature.
In a free electron model, the Fermi energy E_F is defined as the maximum energy of electrons at absolute zero temperature. It is reached by electrons filling up states in k-space (momentum space) up to this energy.
Given:
We want the energy corresponding to the filling of \frac{N_A}{2} electrons, where N_A is Avogadro's number. This state is somewhere below the Fermi energy as it involves fewer electrons than the Fermi level occupies.
The relationship between energy and the number of electrons N\left(E\right) is derived from the density of states for the free electron model:
Thus, we have:
Equating the proportions gives:
Simplifying, we find:
This matches the form given in the problem: E = 2^n \cdot E_F.
Taking logarithms and comparing:
Therefore, n = -\frac{2}{3}.
Thus, the correct value of n is indeed -\frac{2}{3}.
Crystal structures of two metals A and B are two-dimensional square lattices with same lattice constant $a$. Electrons in metals behave as free electrons. The Fermi surfaces corresponding to A and B are shown by solid circles in figures. 
The electron concentrations in A and B are $n_A$ and $n_B$, respectively. The value of $(\frac{n_B}{n_A})$ is
If $X$ is the dimensionality of a free electron gas, the energy ($E$) dependence of density of states is given by $E^{½X-Y}$, where $Y$ is ________.