If $X$ is the dimensionality of a free electron gas, the energy ($E$) dependence of density of states is given by $E^{½X-Y}$, where $Y$ is ________.
The density of states, denoted as $g(E)$, describes the number of available electron states per unit energy interval. For a free electron gas in $X$ dimensions, the density of states is known to depend on energy $E$ with a specific power law.
In $X$ dimensions, the number of electron states within a wavevector magnitude $k$ is proportional to $k^X$. The energy $E$ of a free electron is related to its wavevector magnitude $k$ by the equation $E = \frac{\hbar^2 k^2}{2m}$, where $\hbar$ is the reduced Planck constant and $m$ is the electron mass.
From the energy relation, we can express $k$ in terms of $E$: $k^2 \propto E$ $k \propto E^{\frac{1}{2}}$
Substituting this into the expression for the number of states $N(E)$: $N(E) \propto k^X \propto (E^{\frac{1}{2}})^X = E^{\frac{X}{2}}$
The density of states $g(E)$ is the derivative of $N(E)$ with respect to energy $E$: $g(E) = \frac{dN(E)}{dE}$ $g(E) \propto \frac{d}{dE} \left( E^{\frac{X}{2}} \right)$ $g(E) \propto E^{\left(\frac{X}{2} - 1\right)}$
The problem states that the energy dependence of the density of states is given by $E^{½X-Y}$. We compare this with our derived dependence, $E^{\left(\frac{X}{2} - 1\right)}$:
$ E^{\frac{X}{2}-1} = E^{\frac{1}{2}X-Y} $
Equating the exponents:
$ \frac{X}{2} - 1 = \frac{1}{2}X - Y $
Simplifying the equation:
$ -1 = -Y $
Therefore,
$ Y = 1 $
The value of $Y$ is 1.
Crystal structures of two metals A and B are two-dimensional square lattices with same lattice constant $a$. Electrons in metals behave as free electrons. The Fermi surfaces corresponding to A and B are shown by solid circles in figures. 
The electron concentrations in A and B are $n_A$ and $n_B$, respectively. The value of $(\frac{n_B}{n_A})$ is