The distance between two places can be covered in \(3\frac{1}{2}\) hours at a speed of 62 km/hr. If the speed is increased by 8 km/hr, how much time would be saved?
24 minutes
This problem involves calculating the time saved when the speed of travel increases over a fixed distance. We are given the initial speed and the time taken to cover a certain distance. We first need to find the total distance covered. Then, using the new speed, we can find the new time taken to cover the same distance and finally calculate the difference in time, which is the time saved.
The relationship between speed, distance, and time is given by the formula:
\( \text{Distance} = \text{Speed} \times \text{Time} \)
We are given:
Let's convert the initial time to a decimal or improper fraction for easier calculation:
\( 3\frac{1}{2} \text{ hours} = 3.5 \text{ hours} \)
Now, we can calculate the distance:
\( \text{Distance} = 62 \text{ km/hr} \times 3.5 \text{ hours} \)
\( \text{Distance} = 62 \times \frac{7}{2} \text{ km} \)
\( \text{Distance} = 31 \times 7 \text{ km} \)
\( \text{Distance} = 217 \text{ km} \)
So, the total distance between the two places is 217 km.
The problem states that the speed is increased by 8 km/hr.
New Speed = Initial Speed + Increase in Speed
New Speed = 62 km/hr + 8 km/hr
New Speed = 70 km/hr
Now we need to find the time taken to cover the same distance (217 km) at the new speed (70 km/hr). The formula for time is:
\( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \)
Using the distance and the new speed:
\( \text{New Time} = \frac{217 \text{ km}}{70 \text{ km/hr}} \)
\( \text{New Time} = \frac{217}{70} \text{ hours} \)
Let's simplify the fraction:
\( \frac{217}{70} = \frac{31 \times 7}{10 \times 7} = \frac{31}{10} = 3.1 \text{ hours} \)
So, the new time taken is 3.1 hours.
The time saved is the difference between the initial time and the new time.
Time Saved = Initial Time - New Time
Time Saved = 3.5 hours - 3.1 hours
Time Saved = 0.4 hours
The question asks for the time saved in minutes. We know that 1 hour is equal to 60 minutes.
Time Saved in Minutes = Time Saved in Hours \(\times\) 60 minutes/hour
Time Saved in Minutes = 0.4 hours \(\times\) 60 minutes/hour
Time Saved in Minutes = \(\frac{4}{10} \times 60\) minutes
Time Saved in Minutes = \(4 \times 6\) minutes
Time Saved in Minutes = 24 minutes
Therefore, 24 minutes would be saved if the speed is increased by 8 km/hr.
By first calculating the distance, then the new time required with the increased speed, and finally finding the difference between the original and new travel times, we determined that 24 minutes would be saved.
| Calculation Step | Value / Formula |
|---|---|
| Initial Speed | 62 km/hr |
| Initial Time | \(3\frac{1}{2}\) hours = 3.5 hours |
| Distance | \(62 \times 3.5 = 217\) km |
| New Speed | \(62 + 8 = 70\) km/hr |
| New Time | \(217 / 70 = 3.1\) hours |
| Time Saved (Hours) | \(3.5 - 3.1 = 0.4\) hours |
| Time Saved (Minutes) | \(0.4 \times 60 = 24\) minutes |
Review the key concepts used in this problem:
The concepts of time, speed, and distance are interconnected. If you know any two of these values, you can always find the third using the relevant formula derived from \( \text{Distance} = \text{Speed} \times \text{Time} \). Increasing speed while keeping the distance constant will always decrease the time taken. Conversely, decreasing speed will increase the time taken.
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A man travelled a distance of 42 km in 5 hours. He travelled partly on foot at the rate of 6 km/h and partly on bicycle at the rate of 10 km/h. The distance travelled on foot is:
A train takes \(2\frac{1}{2}\) hours less for a journey of 300 km, if its speed is increased by 20 km/h from its usual speed. How much time will it take to cover a distance of 192 km at its usual speed?