The problem states that the cost price (CP) of 10 articles is equal to the selling price (SP) of 9 articles. We need to find the profit percentage.
Let the cost price of one article be CP and the selling price of one article be SP.
According to the question:
$ 10 \times \text{CP} = 9 \times \text{SP} $
From this equation, we can express the cost price in terms of the selling price:
$ \text{CP} = \frac{9}{10} \times \text{SP} $
Since the cost price ($\frac{9}{10} \times \text{SP}$) is less than the selling price (SP), there is a profit.
Profit = Selling Price - Cost Price
Profit = $ \text{SP} - \text{CP} $
Substitute the value of CP:
Profit = $ \text{SP} - \left( \frac{9}{10} \times \text{SP} \right) $
Profit = $ \left( 1 - \frac{9}{10} \right) \times \text{SP} $
Profit = $ \frac{1}{10} \times \text{SP} $
The formula for profit percentage is:
Profit % = $ \left( \frac{\text{Profit}}{\text{CP}} \right) \times 100\% $
Substitute the values for Profit and CP:
Profit % = $ \left( \frac{\frac{1}{10} \times \text{SP}}{\frac{9}{10} \times \text{SP}} \right) \times 100\% $
Simplify the expression:
Profit % = $ \left( \frac{1}{9} \right) \times 100\% $
Profit % = $ \frac{100}{9} \% $
Convert the improper fraction to a mixed number:
Profit % = $ 11 \frac{1}{9} \% $
Rohit buys 8 pens and 4 pencils for Rs. 2400. He sells pencils at a profit of 20 percent and pens at the loss of 10 percent. If his overall profit is Rs. 240, then what is the sum of the cost price of one pen and one pencil?
A man sells a car to his friend at the loss of 10 %; who in return sells it for Rs. 54000 making a profit of 20 %. What was the initial value of the car?
An article was sold at a loss of 24%. If it were sold for Rs. 1,596 more, then there would have been a gain of 18%, The cost price of the article is:
The cost price of an article is Rs.6,450. If it sold at a profit 16%, how much would be its selling price?
If the selling price of 7 articles is equal to the cost price of 6 articles, then what is the percentage loss?