The correct truth table for the given input data of the following logic gate is :
| Inputs | Output | |||
|---|---|---|---|---|
| A | B | C | D | Y |
| 1 | 1 | 0 | 1 | 0 |
| 0 | 0 | 1 | 1 | 0 |
| 1 | 0 | 1 | 0 | 1 |
| 1 | 1 | 1 | 1 | 1 |
To determine the correct truth table for the given logic gate circuit, let's analyze it step-by-step:
Let's simplify this step-by-step to find the output for different input combinations:
Now we apply the above logic to each of the input combinations:
| Inputs | Output | ||||
|---|---|---|---|---|---|
| A | B | C | D | Y | |
| 1 | 1 | 0 | 1 | 0 | |
| 0 | 0 | 1 | 1 | 0 | |
| 1 | 0 | 1 | 0 | 1 | |
| 1 | 1 | 1 | 1 | 1 | |
Comparing all options, the correct truth table for the given inputs and circuit logic matches the one provided:
| Inputs | Output | |||
|---|---|---|---|---|
| A | B | C | D | Y |
| 1 | 1 | 0 | 1 | 0 |
| 0 | 0 | 1 | 1 | 0 |
| 1 | 0 | 1 | 0 | 1 |
| 1 | 1 | 1 | 1 | 1 |
Assuming in forward bias condition there is a voltage drop of $0.7 \text{ V}$ across a silicon diode, the current through diode $D_1$ in the circuit is ________$\text{mA}$.
(Assume all diodes in the given circuit are identical)

Find the correct combination of A, B, C and D inputs which can cause the LED to glow.

Assuming in forward bias condition there is a voltage drop of $0.7 \text{ V}$ across a silicon diode, the current through diode $D_1$ in the circuit is ________$\text{mA}$.
(Assume all diodes in the given circuit are identical)

Find the correct combination of A, B, C and D inputs which can cause the LED to glow.
