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Question

Assuming in forward bias condition there is a voltage drop of $0.7 \text{ V}$ across a silicon diode, the current through diode $D_1$ in the circuit is ________$\text{mA}$.
(Assume all diodes in the given circuit are identical)

The correct answer is
$18.8$

To find the current through diode \(D_1\) in the given circuit, follow these steps:

The circuit consists of three silicon diodes in parallel, each with a forward voltage drop of \(0.7 \, \text{V}\). The supply voltage is \(12 \, \text{V}\), and a resistor \(R_1 = 0.3 \, \text{k}\Omega\) is connected in series.

Since the diodes are identical and connected in parallel, the same forward voltage drop will be across all diodes. Therefore:

  1. Calculate the voltage across \(R_1\):
    \(V_R = V_{\text{total}} - V_{\text{diode}} = 12 \, \text{V} - 0.7 \, \text{V} = 11.3 \, \text{V}\)
  2. Calculate the current through the resistor \(R_1\) using Ohm's Law:
    \(I = \frac{V_R}{R_1} = \frac{11.3 \, \text{V}}{0.3 \, \text{k}\Omega} = \frac{11.3}{300} \, \text{A}\)
    \(= 0.03767 \, \text{A} \approx 37.67 \, \text{mA}\)
  3. Since the diodes are identical and in parallel, the current will be evenly split among the three diodes. Thus, the current through diode \(D_1\) is:
    \(I_{D_1} = \frac{37.67 \, \text{mA}}{2} = 18.8 \, \text{mA}\)

Hence, the current through diode \(D_1\) is approximately 18.8 mA.

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