The problem states that the area of a rectangle is equal to the area of a square. We are given the length of the rectangle and the side length of the square.
The area of a square is calculated by the formula:
$ \text{Area}_{\text{square}} = \text{side} \times \text{side} $
Given the side of the square is 44 m:
$ \text{Area}_{\text{square}} = 44 \text{ m} \times 44 \text{ m} = 1936 \text{ m}^2 $
Since the area of the rectangle is the same as the area of the square:
$ \text{Area}_{\text{rectangle}} = \text{Area}_{\text{square}} = 1936 \text{ m}^2 $
The area of a rectangle is calculated using the formula:
$ \text{Area}_{\text{rectangle}} = \text{length} \times \text{width} $
We know the area ($1936 \text{ m}^2$) and the length (121 m). We need to find the width.
$ 1936 \text{ m}^2 = 121 \text{ m} \times \text{width} $
To find the width, rearrange the formula:
$ \text{width} = \frac{\text{Area}_{\text{rectangle}}}{\text{length}} $
$ \text{width} = \frac{1936 \text{ m}^2}{121 \text{ m}} $
$ \text{width} = 16 \text{ m} $
The width of the rectangle is 16 m.
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