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Question

Tarun owned a plot of land having an area that was 10% more than the area of the plot owned by Basab, while the area of the plot of land owned by Nakul was 40% more than the area of the plot owned by Tarun. If the area of the plot owned by Nakul was 2695 square feet, what was the area (in square feet) of the plot owned by Basab?

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

1750

Solving the Plot Area Percentage Problem

This problem involves calculating the area of a plot of land based on percentage increases relative to other plots. We are given the area of Nakul's plot and the percentage relationships between Tarun's and Basab's plots, and Tarun's and Nakul's plots.

Understanding the Relationships

Let's define the areas:

  • Area of Basab's plot = \(B\) square feet
  • Area of Tarun's plot = \(T\) square feet
  • Area of Nakul's plot = \(N\) square feet

According to the problem statement:

  • Tarun's area was 10% more than Basab's area.
  • Nakul's area was 40% more than Tarun's area.
  • Nakul's area (\(N\)) was 2695 square feet.

Setting up the Equations

We can write these relationships as equations:

  1. Tarun's area (\(T\)) is Basab's area (\(B\)) plus 10% of \(B\).
    \(T = B + 0.10B\)
    \(T = 1.10B\)
  2. Nakul's area (\(N\)) is Tarun's area (\(T\)) plus 40% of \(T\).
    \(N = T + 0.40T\)
    \(N = 1.40T\)
  3. We are given the value of \(N\).
    \(N = 2695\)

Solving for Basab's Area

We need to find the value of \(B\). We can use the given value of \(N\) and work backwards through the equations.

Step 1: Find Tarun's Area (\(T\))

We know that \(N = 1.40T\) and \(N = 2695\). So, we can write:

\(2695 = 1.40T\)

To find \(T\), we divide 2695 by 1.40:

\(T = \frac{2695}{1.40}\)

\(T = \frac{2695}{\frac{140}{100}} = \frac{2695 \times 100}{140} = \frac{2695 \times 10}{14}\)

Let's perform the division:

\(T = \frac{26950}{14}\)

Dividing 26950 by 14:

Calculation Result
\(26950 \div 14\) 1925

So, Tarun's area (\(T\)) is 1925 square feet.

Step 2: Find Basab's Area (\(B\))

Now we know that \(T = 1.10B\) and \(T = 1925\). So, we can write:

\(1925 = 1.10B\)

To find \(B\), we divide 1925 by 1.10:

\(B = \frac{1925}{1.10}\)

\(B = \frac{1925}{\frac{110}{100}} = \frac{1925 \times 100}{110} = \frac{1925 \times 10}{11}\)

Let's perform the division:

\(B = \frac{19250}{11}\)

Dividing 19250 by 11:

Calculation Result
\(19250 \div 11\) 1750

So, Basab's area (\(B\)) is 1750 square feet.

Conclusion

The area of the plot owned by Basab was 1750 square feet.

Revision Table: Plot Area Problem

Person Relationship to Previous Area Calculation Area (sq ft)
Nakul Given \(N = 2695\) 2695
Tarun \(N = 1.40T\) \(T = N / 1.40 = 2695 / 1.40\) 1925
Basab \(T = 1.10B\) \(B = T / 1.10 = 1925 / 1.10\) 1750

Additional Information: Percentage Calculations

When a quantity is increased by a certain percentage, you can calculate the new quantity by multiplying the original quantity by \((1 + \text{percentage increase as a decimal})\). For example:

  • A 10% increase means multiplying by \((1 + 0.10) = 1.10\).
  • A 40% increase means multiplying by \((1 + 0.40) = 1.40\).

Conversely, if you know the new quantity after a percentage increase and want to find the original quantity, you divide the new quantity by \((1 + \text{percentage increase as a decimal})\).

In this problem, Nakul's area is 140% of Tarun's area (\(N = 1.40T\)), and Tarun's area is 110% of Basab's area (\(T = 1.10B\)). We used the division method to find the original values.

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Important Questions from Percentage

  1. A number p increased by p% of 99 equals 99 increased by 99% of p. What is (p + 51)% of 928 + 72?

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  3. What is 12% of 4% of 7% of 2 × 10 6 ?

  4. Vignesh spends 42% of his monthly salary on food, 16% on house rent, 11% on entertainment and 7% on conveyance. But due to some family function, he has to borrow Rs. 12,000 from a money leader to meet the expenses of Rs. 18,000 What is his monthly salary?

  5. If X is 12.25% more than Y. then Y is approximately_____ less than X.

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