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Question

If, in a competitive exam, the marks obtained by Sam are 19% less than those of Peter, then the marks obtained by Peter are how much percentage more than the marks obtained by Sam? (Correct to two decimal places)

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

23.46%

Calculating Percentage Difference in Competitive Exam Marks

This problem asks us to find the percentage by which Peter's marks are more than Sam's marks, given that Sam's marks are 19% less than Peter's marks in a competitive exam.

Understanding the Relationship Between the Marks

Let's denote Peter's marks by \(P\) and Sam's marks by \(S\).

We are told that Sam's marks are 19% less than Peter's marks. This means Sam's marks are equal to Peter's marks minus 19% of Peter's marks.

We can write this relationship mathematically:

\(S = P - 19\%\) of \(P\)

\(S = P - \frac{19}{100} \times P\)

\(S = P - 0.19P\)

\(S = (1 - 0.19)P\)

\(S = 0.81P\)

This equation tells us that Sam's marks are 0.81 times Peter's marks.

Calculating the Percentage More

Now, we want to find by what percentage Peter's marks (\(P\)) are more than Sam's marks (\(S\)). To do this, we need to find the difference between their marks (\(P - S\)) and express this difference as a percentage of Sam's marks (\(S\)), because we are comparing Peter's marks to Sam's marks.

The formula for percentage increase is:

\(\text{Percentage Increase} = \frac{\text{Difference}}{\text{Base Value}} \times 100\%\)

Here, the Difference is \(P - S\), and the Base Value is \(S\).

\(\text{Percentage More} = \frac{P - S}{S} \times 100\%\)

We know that \(S = 0.81P\). We can substitute this into the formula:

\(\text{Percentage More} = \frac{P - 0.81P}{0.81P} \times 100\%\)

\(\text{Percentage More} = \frac{(1 - 0.81)P}{0.81P} \times 100\%\)

\(\text{Percentage More} = \frac{0.19P}{0.81P} \times 100\%\)

We can cancel out \(P\) from the numerator and the denominator:

\(\text{Percentage More} = \frac{0.19}{0.81} \times 100\%\)

\(\text{Percentage More} = \frac{19}{81} \times 100\%\)

\(\text{Percentage More} = \frac{1900}{81}\%\)

Performing the Calculation and Rounding

Now, we calculate the numerical value:

\(\frac{1900}{81} \approx 23.45679...\%\)

The question asks for the answer correct to two decimal places. We look at the third decimal place, which is 6. Since 6 is 5 or greater, we round up the second decimal place.

\(23.45679...\% \approx 23.46\%\)

So, the marks obtained by Peter are approximately 23.46% more than the marks obtained by Sam.

Revision Table: Key Percentage Formulas

Concept Formula Notes
Percentage Change \(\frac{\text{Change}}{\text{Original Value}} \times 100\%\) Change = New Value - Original Value
Value After % Decrease Original Value \(\times\) \((1 - \frac{\text{% Decrease}}{100})\) Example: 20% decrease from 100 is \(100 \times (1 - 0.20) = 80\).
Value After % Increase Original Value \(\times\) \((1 + \frac{\text{% Increase}}{100})\) Example: 20% increase from 100 is \(100 \times (1 + 0.20) = 120\).
Finding Original Value from % Decrease New Value / \((1 - \frac{\text{% Decrease}}{100})\) If 80 is 20% less than Original, Original = \(80 / (1 - 0.20) = 80 / 0.80 = 100\).

Additional Information on Percentage Calculations

  • Percentage problems often require careful reading to identify the correct base value for the calculation. In this problem, the base changes from Peter's marks (for Sam's decrease) to Sam's marks (for Peter's increase).
  • A percentage decrease from value A to value B will result in a different percentage increase from value B to value A, unless the percentage change is 0%.
  • These types of questions test your understanding of relative change. They are common in aptitude tests and competitive exams.
  • Practicing with different percentage values will help solidify the concept and speed up calculation in exams.
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Similar Questions

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Important Questions from Percentage

  1. A number p increased by p% of 99 equals 99 increased by 99% of p. What is (p + 51)% of 928 + 72?

  2. Amina saves 16% of her income. Now her income is increased by 20% but she still saves the same amount as before. What is the percentage increase in her expenditure?

  3. What is 12% of 4% of 7% of 2 × 10 6 ?

  4. Vignesh spends 42% of his monthly salary on food, 16% on house rent, 11% on entertainment and 7% on conveyance. But due to some family function, he has to borrow Rs. 12,000 from a money leader to meet the expenses of Rs. 18,000 What is his monthly salary?

  5. If X is 12.25% more than Y. then Y is approximately_____ less than X.

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