Suppose the number of accidents per week on a certain highway follows Poisson distribution with mean 2 then the percentage of weeks having no accidents is .................... (Given e-2 = 0.1353)
13.53%
For a Poisson distribution with mean m, P(X = x) = e-m mx / x!.
No accidents means x = 0 and m = 2, so P(X = 0) = e-2 x 20 / 0! = e-2 = 0.1353.
Percentage of weeks with no accidents = 0.1353 x 100 = 13.53%.
Hence, the answer is 13.53%.
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Important Questions from Probability
- If one event is unaffected by the outcome of another event, the two events are said to be:
1. Dependent
2. Independent
3. Mutually exclusive
4. Mutually inclusive - Let $M$ be a randomly chosen non-empty subset of $S = \{1, 2, 3, \dots, 2026\}$.
Which of the following is the probability that the product of all the elements of $M$ is even? - A fair coin is tossed 6 times. The probability of getting at least 5 heads is _________________. (rounded off to two decimal places)
- Consider a random experiment of rolling a fair die. The probability of getting an odd number or a number less than 4 is ______ (Rounded off to two decimal places).
- In a null hypothesis significance test, the significance level $\alpha$ was set to 0.01. For which one or more of the following $p$ values would the null hypothesis be rejected?
