A box contains 8 white and 3 red balls. If two balls are drawn at random, find the probability that one is white and one is red.
24/55
Total balls = 8 + 3 = 11. Number of ways of drawing 2 balls: \(^{11}C_2=\frac{11\times 10}{2}=55\).
Favourable ways (1 white and 1 red): \(^{8}C_1\times {}^{3}C_1=8\times 3=24\).
Required probability \(=\frac{24}{55}\).
Hence, the answer is 24/55.
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Important Questions from Probability
- If one event is unaffected by the outcome of another event, the two events are said to be:
1. Dependent
2. Independent
3. Mutually exclusive
4. Mutually inclusive - Let $M$ be a randomly chosen non-empty subset of $S = \{1, 2, 3, \dots, 2026\}$.
Which of the following is the probability that the product of all the elements of $M$ is even? - A fair coin is tossed 6 times. The probability of getting at least 5 heads is _________________. (rounded off to two decimal places)
- Consider a random experiment of rolling a fair die. The probability of getting an odd number or a number less than 4 is ______ (Rounded off to two decimal places).
- In a null hypothesis significance test, the significance level $\alpha$ was set to 0.01. For which one or more of the following $p$ values would the null hypothesis be rejected?
