For a normal curve with mean of 120 and standard deviation of 35, what proportion (in percent) of the area under the curve will lie between the values of 85 and 155 ?
68.26
Convert both limits to z-scores using z = (x - mean)/SD. For 85: z = (85 - 120)/35 = -35/35 = -1. For 155: z = (155 - 120)/35 = 35/35 = +1.
So the required area lies within one standard deviation on either side of the mean.
From the standard normal table, P(0 < Z < 1) = 0.3413, so P(-1 < Z < 1) = 2 x 0.3413 = 0.6826, i.e. 68.26 percent (the empirical 68-95-99.7 rule).
Hence, the answer is 68.26.
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