Finding the Sum of Zeros for \(3x^2+2x-5\)
For a quadratic equation in the standard form \(ax^2+bx+c=0\), the sum of its zeros (roots) is given by the formula:
Sum of zeros = \(\boldsymbol{-b/a}\)
Identify Coefficients
In the given equation, \(3x^2+2x-5 = 0\):
- \(a = 3\)
- \(b = 2\)
- \(c = -5\)
Calculate the Sum of Zeros
Using the formula:
Sum of zeros = \(\boldsymbol{-b/a} = \boldsymbol{-(2)/(3)}\)
Sum of zeros = \(\boldsymbol{-2/3}\)
Conclusion
The sum of the zeros for the equation \(3x^2+2x-5\) is \(\boldsymbol{-2/3}\).
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If \(\tan \left( {\frac{α }{2}} \right)\) and \(\tan \left( {\frac{β }{2}} \right)\) are the roots of the equation 8x 2- 26x + 15 = 0, then the value of cos (α + β) will be
