$4x^2 + 4x - 3 = 0$
$-\frac{3}{2}, \frac{1}{2}$
To find the roots of the quadratic equation $4x^2 + 4x - 3 = 0$, we can use the factorization method.
$4x^2 + 6x - 2x - 3 = 0$
$2x(2x + 3) - 1(2x + 3) = 0$
$(2x - 1)(2x + 3) = 0$
The roots of the equation $4x^2 + 4x - 3 = 0$ are $x = \frac{1}{2}$ and $x = -\frac{3}{2}$.
If (x - 1) 2+ (y - 2) 2= (x – 1) (y - 2), where x and y are integers, then value of 2x + 3y is: