Specialization Lattice stands for
An entity type can participate as a subclass in more than one specialization.
In the enhanced ER model, if every subclass takes part in only one specialization, the structure is a hierarchy (tree).
When a subclass can take part as a subclass in more than one specialization, i.e. it may have several superclasses, the structure becomes a specialization lattice and the subclass is a shared subclass.
So a lattice is defined by participation in more than one specialization.
Hence, An entity type can participate as a subclass in more than one specialization.
What kind of mechanism is to be taken into account for converting a weak entity set into strong entity set in entity-relationship diagram ?
Which of the following provides the best description of an entity type ?
Let \(E_{1}\) and \(E_{2}\) be two entities in E-R diagram with simple single valued attributes. \(R_{1}\) and \(R_{2}\) are two relationships between \(E_{1}\) and \(E_{2}\) where \(R_{1}\) is one - many and \(R_{2}\) is many - many. \(R_{1}\) and \(R_{2}\) do not have any attribute of their own. How many minimum number of tables are required to represent this situation in the Relational Model ?
Which of the following statements is FALSE about weak entity set ?
For a weak entity set to be meaningful, it must be associated with another entity set in combination with some of their attribute values, is called as :
Let pk(R) denotes primary key of relation R. A many-to-one relationship that exists between two relations R1 and R2 can be expressed as follows :
The values of the attributes in a database describe a particular _______.
Which of the following data item is not broken down into smaller units is?
Which of the following statements is/are TRUE?
(i) A weak entity set is identified solely by its partial key (discriminator).
(ii) The identifying relationship type between a weak entity type and its owner entity type must have total participation from the weak entity type.