Simplify \(\left\{\left(\dfrac{13}{33}\right)\div\left(\dfrac{13}{7}\right)\right\}\div\left(\dfrac28\times\dfrac{16}{6}+\dfrac{5}{11}\right)+\dfrac73\div\dfrac{37}{20}\text{ of }\dfrac{20}{3}\)
\(\tfrac{14}{37}\)
\(\dfrac{13/33}{13/7} = \dfrac{13}{33}\times\dfrac{7}{13} = \dfrac{7}{33}\).
Inside the bracket: \(\dfrac28\times\dfrac{16}{6} = \dfrac23\), plus \(\dfrac{5}{11}\) gives \(\dfrac23+\dfrac{5}{11} = \dfrac{22+15}{33} = \dfrac{37}{33}\).
First part: \(\dfrac{7}{33}\div\dfrac{37}{33} = \dfrac{7}{37}\).
For the second part, \(\dfrac73\) and \(\dfrac{37}{20}\text{ of }\dfrac{20}{3} = \dfrac{37}{3}\), so \(\dfrac73\div\dfrac{37}{3} = \dfrac{7}{37}\).
Adding both parts: \(\dfrac{7}{37}+\dfrac{7}{37} = \dfrac{14}{37}\).
Hence, the simplified value of the expression is \(\tfrac{14}{37}\).
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The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:
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