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Question

Solve the following.

$4 \times 36 - 6[3 + 2(216 \div 6) - 51] = ?$

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
0

Mathematical Expression Solution

We need to solve the given mathematical expression following the order of operations (PEMDAS/BODMAS): Parentheses/Brackets, Exponents/Orders, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

The expression is: $4 \times 36 - 6[3 + 2(216 \div 6) - 51]$

Step-by-Step Calculation

  • Step 1: Solve the division inside the innermost parenthesis.

    Calculate $216 \div 6$.

    $216 \div 6 = 36$

  • Step 2: Solve the expression inside the main parenthesis.

    Substitute the result from Step 1 back into the expression within the brackets:

    $3 + 2(36) - 51$

    Perform multiplication:

    $3 + 72 - 51$

    Perform addition and subtraction from left to right:

    $75 - 51 = 24$

  • Step 3: Perform multiplication outside the brackets.

    Multiply the result from Step 2 by 6:

    $6 \times 24 = 144$

  • Step 4: Perform the initial multiplication and final subtraction.

    First, calculate $4 \times 36$.

    $4 \times 36 = 144$

    Now, subtract the result from Step 3 from this value:

    $144 - 144 = 0$

Final Answer

The result of the calculation $4 \times 36 - 6[3 + 2(216 \div 6) - 51]$ is 0.

This corresponds to Option B.

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Important Questions from Bodmas Rule

  1. The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:

  2. The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:

  3. The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:

  4. The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:

  5. The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is:

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