$4 \times 36 - 6[3 + 2(216 \div 6) - 51] = ?$
We need to solve the given mathematical expression following the order of operations (PEMDAS/BODMAS): Parentheses/Brackets, Exponents/Orders, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).
The expression is: $4 \times 36 - 6[3 + 2(216 \div 6) - 51]$
Step 1: Solve the division inside the innermost parenthesis.
Calculate $216 \div 6$.
$216 \div 6 = 36$
Step 2: Solve the expression inside the main parenthesis.
Substitute the result from Step 1 back into the expression within the brackets:
$3 + 2(36) - 51$
Perform multiplication:
$3 + 72 - 51$
Perform addition and subtraction from left to right:
$75 - 51 = 24$
Step 3: Perform multiplication outside the brackets.
Multiply the result from Step 2 by 6:
$6 \times 24 = 144$
Step 4: Perform the initial multiplication and final subtraction.
First, calculate $4 \times 36$.
$4 \times 36 = 144$
Now, subtract the result from Step 3 from this value:
$144 - 144 = 0$
The result of the calculation $4 \times 36 - 6[3 + 2(216 \div 6) - 51]$ is 0.
This corresponds to Option B.
Simplify the given expression using BODMAS.
$\frac{4}{11} \times \frac{121}{16} \times 24 (75^2 - 55^2) \times \frac{1}{100}$
Simplify the given expression.
$\frac{5+5\times5}{5\times5+5} \times \frac{\frac{1}{5}\div(\frac{1}{5}\times\frac{1}{5})}{(\frac{1}{5}\times\frac{1}{5})\div\frac{1}{5}} - (5 - \frac{1}{5}) \times \frac{10}{2}$
The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:
The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:
The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:
The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:
The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is: