Simplify: \(\dfrac{\left(\frac{13}{21}\right)}{\left(\frac{13}{10}\right)} \div \left(\dfrac{5}{9}\times\dfrac{18}{15}+\dfrac{5}{7}\right)+\dfrac{10}{6}\div\dfrac{29}{15}\text{ of }\dfrac{15}{6}\)
\(\tfrac{20}{29}\)
\(\dfrac{13/21}{13/10} = \dfrac{13}{21}\times\dfrac{10}{13} = \dfrac{10}{21}\).
Inside the bracket: \(\dfrac59\times\dfrac{18}{15} = \dfrac23\), plus \(\dfrac57\) gives \(\dfrac23+\dfrac57 = \dfrac{29}{21}\).
First part: \(\dfrac{10}{21}\div\dfrac{29}{21} = \dfrac{10}{29}\).
For the second part, \(\dfrac{10}{6}=\dfrac53\), and \(\dfrac{29}{15}\text{ of }\dfrac{15}{6} = \dfrac{29}{6}\), so \(\dfrac53\div\dfrac{29}{6} = \dfrac53\times\dfrac{6}{29} = \dfrac{10}{29}\).
Adding both parts: \(\dfrac{10}{29}+\dfrac{10}{29} = \dfrac{20}{29}\).
Hence, the simplified value of the expression is \(\tfrac{20}{29}\).
Simplify the given expression using BODMAS.
$\frac{4}{11} \times \frac{121}{16} \times 24 (75^2 - 55^2) \times \frac{1}{100}$
The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:
The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:
The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:
The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:
The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is: