The bob of a simple pendulum is displaced from its mean position and then released from rest 0.20 m above its mean position. What is the speed of the bob as it passes through the mean position? (Take \(g = 10 \, m/s^2\))
2 m/s
By conservation of mechanical energy, the potential energy of the bob at 0.20 m above the mean position converts entirely into kinetic energy at the mean position: \(mgh = \frac{1}{2}mv^2\), so \(v = \sqrt{2gh}\). Substituting \(g = 10 \, m/s^2\) and \(h = 0.20 \, m\): \(v = \sqrt{2 \times 10 \times 0.20} = \sqrt{4} = 2 \, m/s\). So the bob's speed at the mean position is 2 m/s.
Similar Questions
Which one of the following statements regarding simple pendulum is correct?
Simple pendulum has a time period independent of amplitude:
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Which one of the following statements regarding simple pendulum is correct?
Simple pendulum has a time period independent of amplitude:
