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Question

The period (T) for the pendulum with length (l) and placed at the gravitational acceleration (g) is given by:

The correct answer is \(T = 2\pi \sqrt {\frac{l}{g}}\)

Finding the Period of a Simple Pendulum

A simple pendulum is a basic physics concept consisting of a point mass (bob) suspended from a string or rod of negligible mass, free to swing back and forth. The time it takes for the pendulum to complete one full swing (from one side to the other and back) is called its period (T).

Factors Affecting the Period of a Pendulum

The period of a simple pendulum depends on two main factors:

  • The length of the pendulum (l).
  • The acceleration due to gravity (g) at the location of the pendulum.

Interestingly, for small angles of displacement, the period of a simple pendulum does not depend on the mass of the bob or the amplitude of the swing.

Formula for the Period of a Simple Pendulum

The relationship between the period (T), length (l), and gravitational acceleration (g) for a simple pendulum is a well-established formula in physics. This formula is derived using principles of mechanics and differential equations, often approximated for small angles of oscillation.

The standard formula for the period of a simple pendulum is given by:

\(\text{T} = 2\pi \sqrt {\frac{l}{g}}\)

Here:

  • \(T\) is the period of oscillation.
  • \(\pi\) is the mathematical constant Pi, approximately equal to 3.14159.
  • \(l\) is the length of the pendulum string or rod.
  • \(g\) is the acceleration due to gravity.

Comparing with the Options

Let's look at the given options for the period (T) formula:

  1. \(T = 2\pi \sqrt {\frac{l}{g}}\)
  2. \(T = 2\pi \sqrt {lg}\)
  3. \(T = 3\pi \sqrt {\frac{l}{g}}\)
  4. \(T = 3\pi \sqrt {lg}\)

Comparing these options with the standard formula \(T = 2\pi \sqrt {\frac{l}{g}}\), we can see which option correctly represents the period of a simple pendulum with length \(l\) and gravitational acceleration \(g\).

Option 1 matches the correct formula exactly.

Option 2 incorrectly places \(lg\) inside the square root instead of \(\frac{l}{g}\).

Options 3 and 4 incorrectly use \(3\pi\) instead of \(2\pi\).

Therefore, the correct formula for the period of a simple pendulum is \(T = 2\pi \sqrt {\frac{l}{g}}\).

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Important Questions from Pendulums

  1. What will be the time period of oscillation, if the length of a second pendulum is one third?

  2. Two pendulums oscillate with a constant phase difference of 90°. If time period of one of them is 2 sec., then period of the other is

  3. Two pendulums of length $169$ cm and $144$ cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

  4. Which one of the following statements regarding simple pendulum is correct?

    Simple pendulum has a time period independent of amplitude:

  5. If a simple pendulum takes 40 seconds to complete 20 oscillations, then the time period of the simple pendulum is

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