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Question

If a simple pendulum takes 40 seconds to complete 20 oscillations, then the time period of the simple pendulum is

The correct answer is

2 second

Understanding the Simple Pendulum Time Period

The time period of a simple pendulum is defined as the time taken for one complete oscillation. A complete oscillation means the pendulum bob starts from a point, moves to one extreme, then to the other extreme, and finally returns to the starting point.

In this question, we are given the total time taken for a certain number of oscillations for a simple pendulum.

  • Total time given = 40 seconds
  • Number of oscillations completed = 20

To find the time period, we need to find the time taken for just one oscillation. The formula to calculate the time period (T) of a simple pendulum is:

$$\text{Time Period (T)} = \frac{\text{Total Time}}{\text{Number of Oscillations}}$$

Calculating the Simple Pendulum Time Period

Using the given values in the formula:

$$T = \frac{40 \text{ seconds}}{20 \text{ oscillations}}$$

$$T = 2 \text{ seconds/oscillation}$$

So, the simple pendulum takes 2 seconds to complete one full oscillation. This value represents the simple pendulum time period.

The concept of time period is crucial when studying periodic motion, such as the motion of a simple pendulum. It helps us understand the frequency of oscillations, which is the number of oscillations per unit time.

In this specific case, the time period of the simple pendulum is found to be 2 seconds based on the provided data of 40 seconds for 20 oscillations. Understanding the relationship between total time, number of oscillations, and the time period is fundamental in physics problems involving oscillating systems like the simple pendulum.

The calculated simple pendulum time period matches one of the given options.

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Important Questions from Pendulums

  1. What will be the time period of oscillation, if the length of a second pendulum is one third?

  2. Two pendulums oscillate with a constant phase difference of 90°. If time period of one of them is 2 sec., then period of the other is

  3. The period (T) for the pendulum with length (l) and placed at the gravitational acceleration (g) is given by:

  4. Two pendulums of length $169$ cm and $144$ cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

  5. Which one of the following statements regarding simple pendulum is correct?

    Simple pendulum has a time period independent of amplitude:

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