When written as a recurring decimal, \(\dfrac{1}{7}\) is equal to:
\(0.\overline{142857}\)
The fraction \(\dfrac{1}{7}\) gives a non-terminating repeating decimal on division.
Dividing 1 by 7, the sequence of digits 142857 keeps repeating without change.
So \(\dfrac{1}{7} = 0.142857142857\ldots\), commonly written with a bar over the block 142857.
Hence, \(0.\overline{142857}\).
Similar Questions
The number \(1.\overline{074}\), when written in the form \(\dfrac{p}{q}\), is equal to:
The product of two numbers is 1.728. If one of the numbers is 6.4, then the other number will be:
x and y, given correct to 2 decimal places, are 3.57 and 3.42 respectively. What is the upper bound of \(x + y\)?
How much must be added to the difference of 5.62 and 3.76 to make 10?
The fraction from the ones listed below that will not lead to a recurring decimal is:
If \(123 \times 456 = 56088\), then \(0.123 \times 0.0456 = ?\)
If \(43 \times 36 = 1548\), what is the value of \(0.001548 \div 3.6\)?
Solve the below equation.
\(34.508 + 3.4508 + 345.08 - 32.89 = ?\)x and y, given correct to 2 decimal places, are 3.57 and 3.42 respectively. What is the upper bound of \(x + y\)?
If \(23 \times 31 = 713\), then \(0.00713 \div 3.1\) is equal to:
Important Questions from Decimals
What is the result when 0.129129129… is converted to a fraction?
Which of the following statement(s) is/are correct?
I. (3/11) > 0.3
II. (7/8) > 0.86
The value of \(1.\overline{3}+0.\overline{69}-0.5\overline{23}\) is equal to:
The value of \(0.\bar 4 + 0.5 \bar 9 - 0.4 \overline{23}\) is equal to:
Find the sum of \(\frac{0.01}{0.1}+\frac{0.1}{0.01}\)
