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Question

Rishu deposited an amount of Rs. 950 at Compound Interest. The amount gets doubled of itself after 4 years. What will be the amount after 12 years?

This question was previously asked in
RBI Assistant Prelims Memory Based Paper (27 March 2022) (Shift 2)
The correct answer is

Rs. 7600

Understanding Compound Interest and Doubling Time

This problem involves calculating the future amount based on compound interest principles, specifically focusing on the concept of doubling time.

We are given:

  • Principal Amount ($P$): Rs. 950
  • Time for the amount to double: 4 years
  • Target Time: 12 years

Calculating the Amount After 12 Years

Compound interest means that the interest earned also earns interest over time. When an amount doubles in a certain period, it signifies a specific growth factor over that duration.

Let the principal amount be $P$. According to the question, the amount doubles itself after 4 years. This means the amount after 4 years is $2P$.

Using the compound interest formula, $A = P(1+r)^t$, where:

  • $A$ is the future value of the investment/loan, including interest
  • $P$ is the principal investment amount (the initial deposit or loan amount)
  • $r$ is the annual interest rate (as a decimal)
  • $t$ is the number of years the money is invested or borrowed for

From the information given, after 4 years ($t=4$), the amount $A_4 = 2P$. So, we can write:

$$2P = P(1+r)^4$$

Dividing both sides by $P$, we get:

$$2 = (1+r)^4$$

This equation tells us that the growth factor over 4 years is 2.

Now, we need to find the amount after 12 years ($A_{12}$). Using the same formula:

$$A_{12} = P(1+r)^{12}$$

We can rewrite the term $(1+r)^{12}$ using the information we have:

$$ (1+r)^{12} = (1+r)^{4 \times 3} = ((1+r)^4)^3 $$

Since we know that $(1+r)^4 = 2$, we can substitute this value:

$$ ((1+r)^4)^3 = (2)^3 = 8 $$

Now substitute this back into the formula for $A_{12}$:

$$ A_{12} = P \times 8 $$

We are given the principal amount $P = 950$. Plugging this value in:

$$ A_{12} = 950 \times 8 $$

$$ A_{12} = 7600 $$

Therefore, the amount after 12 years will be Rs. 7600.

Final Answer Summary

The initial deposit is Rs. 950. The investment doubles every 4 years. Over 12 years, there are $12 \div 4 = 3$ doubling periods.

  • After 4 years: Rs. 950 * 2 = Rs. 1900
  • After 8 years: Rs. 1900 * 2 = Rs. 3800
  • After 12 years: Rs. 3800 * 2 = Rs. 7600

Alternatively, the amount after 12 years is $P \times 2^{(12/4)} = 950 \times 2^3 = 950 \times 8 = 7600$.

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Similar Questions

  1. Amar borrowed Rs. 10000 from Sachin at simple interest. After 4 years, Sachin received Rs. 5000 more than the amount given to Amar on loan. Find the rate of interest.

  2. Simple interest accrued on the amount of Rs.14,000 is Rs. 1260 at the rate of 3 % per annum for t years. What would be the compound interest accrued on the same amount for the same years at 10 % per annum compounded annually?


Important Questions from Interest

  1. Three years ago, the value of a flat was Rs. 65,00,000. Its value depreciated at the rate of 5%, 4% and 3% at the end of the first, the second and the third year, respectively. What is its present value?

  2. An electric bulb was bought at Rs. 4200 Its value depreciates at the rate of 8% per annum Its value after one year will be:

  3. What is the amount of money invested after 4 years at the rate of simple interest rate of 13% per annum invested at 4,950 rupees. (In rupees)

  4. A certain sum of money amounts to \(\frac{3}{2}\) of itself in 2 years applying simple interest. Find the rate of simple interest per annum.

  5. A sum of Rs. 2000 will become Rs. 2400 in 12 months at some rate of simple interest. Find the rate of interest per annum. 

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