Rishu deposited an amount of Rs. 950 at Compound Interest. The amount gets doubled of itself after 4 years. What will be the amount after 12 years?
Rs. 7600
This problem involves calculating the future amount based on compound interest principles, specifically focusing on the concept of doubling time.
We are given:
Compound interest means that the interest earned also earns interest over time. When an amount doubles in a certain period, it signifies a specific growth factor over that duration.
Let the principal amount be $P$. According to the question, the amount doubles itself after 4 years. This means the amount after 4 years is $2P$.
Using the compound interest formula, $A = P(1+r)^t$, where:
From the information given, after 4 years ($t=4$), the amount $A_4 = 2P$. So, we can write:
$$2P = P(1+r)^4$$
Dividing both sides by $P$, we get:
$$2 = (1+r)^4$$
This equation tells us that the growth factor over 4 years is 2.
Now, we need to find the amount after 12 years ($A_{12}$). Using the same formula:
$$A_{12} = P(1+r)^{12}$$
We can rewrite the term $(1+r)^{12}$ using the information we have:
$$ (1+r)^{12} = (1+r)^{4 \times 3} = ((1+r)^4)^3 $$
Since we know that $(1+r)^4 = 2$, we can substitute this value:
$$ ((1+r)^4)^3 = (2)^3 = 8 $$
Now substitute this back into the formula for $A_{12}$:
$$ A_{12} = P \times 8 $$
We are given the principal amount $P = 950$. Plugging this value in:
$$ A_{12} = 950 \times 8 $$
$$ A_{12} = 7600 $$
Therefore, the amount after 12 years will be Rs. 7600.
The initial deposit is Rs. 950. The investment doubles every 4 years. Over 12 years, there are $12 \div 4 = 3$ doubling periods.
Alternatively, the amount after 12 years is $P \times 2^{(12/4)} = 950 \times 2^3 = 950 \times 8 = 7600$.
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