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Question

Refer to the following series and answer the question that follows. Counting to be done from left to right. All numbers are single-digit numbers only.
(Left) 3 5 6 3 4 6 4 3 1 5 7 6 8 6 3 1 3 6 7 8 9 7 5 (Right)
How many such odd digits are there, each of which is immediately preceded by an even digit and also immediately followed by an odd digit?

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is
THREE

Series Digit Pattern

We need to analyze the given number series to find specific digit patterns. The series is:

\(3 5 6 3 4 6 4 3 1 5 7 6 8 6 3 1 3 6 7 8 9 7 5\)

The criteria for counting are:

  • The digit must be odd (1, 3, 5, 7, 9).
  • It must be immediately preceded by an even digit (2, 4, 6, 8).
  • It must be immediately followed by an odd digit (1, 3, 5, 7, 9).

This translates to finding the pattern: Even - Odd - Odd.

Odd Digit Identification

Let's scan the series and identify triplets that match the Even - Odd - Odd pattern:

  • \(... 4 3 1 ...\) : The central digit '3' is odd. It's preceded by '4' (even) and followed by '1' (odd). This is a match.
  • \(... 6 3 1 ...\) : The central digit '3' is odd. It's preceded by '6' (even) and followed by '1' (odd). This is a match.
  • \(... 8 9 7 ...\) : The central digit '9' is odd. It's preceded by '8' (even) and followed by '7' (odd). This is a match.

Checking other potential triplets confirms no other matches:

  • \(6 3 4\) is Even-Odd-Even.
  • \(4 6 4\) is Even-Even-Even.
  • \(6 4 3\) is Even-Even-Odd (middle is even).
  • \(3 1 5\) is Odd-Odd-Odd (preceding is odd).
  • \(7 6 8\) is Odd-Even-Even.
  • \(8 6 3\) is Even-Even-Odd (middle is even).
  • \(3 6 7\) is Odd-Even-Odd (preceding is odd).
  • \(6 7 8\) is Even-Odd-Even.
  • \(7 8 9\) is Odd-Even-Odd (preceding is odd).

Count Calculation

We identified exactly three instances where an odd digit is immediately preceded by an even digit and immediately followed by an odd digit.

The qualifying digits are:

  • The first '3' (in 4 3 1)
  • The second '3' (in 6 3 1)
  • The '9' (in 8 9 7)

Thus, the total count is THREE.

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