To find the shortest distance and direction from Puja's final stop (Point P) back to the starting point (Point A), we can track his movements using coordinates.
Let Point A be the origin, represented as \((0, 0)\) on a coordinate plane, where North is the positive y-axis and East is the positive x-axis.
Puja stops at Point P, located at coordinates \((-1, 0)\). He needs to return to Point A, located at \((0, 0)\).
The required displacement vector from P to A is calculated as:
\( \text{Displacement} = A - P = (0, 0) - (-1, 0) \) \( \text{Displacement} = (0 - (-1), 0 - 0) = (1, 0) \)The resulting displacement vector is \((1, 0)\). This indicates a movement of 1 km in the positive x-direction (East) and 0 km in the y-direction.
Therefore, to reach Point A again from Point P, Puja needs to drive 1 km to the east.
A man starts from ‘O’, travels 20 km towards East to reach point ‘A’, turns right and travels 10 km to reach point ‘B’, turns right and travels 9 km to reach point ‘C’, turns right and travels 5 km to reach point ‘D’, turns left and travels 11 km and stops for some time and travels 1 km to reach point ‘E’ and then turns right and travels 6 km to reach point ‘F’.
What is the shortest distance between point ‘A’ and point ‘D’?
In the morning X and Y are walking towards each other in a park. When they meet, Y's shadow' falls upon X. In which direction was X facing?
Two workers K and L start walking from the same point. K walks 5 km North, then turns right and walks 2 km. Meanwhile, L walks 3 km West, then turns South and walks 4 km. Finally L turns left and walks 5 km. Where is K with respect to L?