A man starts from ‘O’, travels 20 km towards East to reach point ‘A’, turns right and travels 10 km to reach point ‘B’, turns right and travels 9 km to reach point ‘C’, turns right and travels 5 km to reach point ‘D’, turns left and travels 11 km and stops for some time and travels 1 km to reach point ‘E’ and then turns right and travels 6 km to reach point ‘F’.
What is the shortest distance between point ‘A’ and point ‘D’?
Let's trace the path the man takes from his starting point 'O' and determine the coordinates of each point mentioned. We can assume 'O' is at the origin (0,0) of a coordinate system. East is the positive x-direction, West is the negative x-direction, North is the positive y-direction, and South is the negative y-direction.
We are asked to find the shortest distance between point 'A' and point 'D'.
Point 'A' has coordinates (20, 0).
Point 'D' has coordinates (11, -5).
The shortest distance between two points in a coordinate system can be found using the distance formula, which is derived from the Pythagorean theorem.
The distance formula between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:
\( \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)
Here, let's take Point 'A' as \((x_1, y_1) = (20, 0)\) and Point 'D' as \((x_2, y_2) = (11, -5)\).
Substitute these coordinates into the distance formula:
\( \text{Distance AD} = \sqrt{(11 - 20)^2 + (-5 - 0)^2} \)
Calculate the differences in the x and y coordinates:
\( \text{Distance AD} = \sqrt{(-9)^2 + (-5)^2} \)
Square the differences:
\( \text{Distance AD} = \sqrt{81 + 25} \)
Add the squared values:
\( \text{Distance AD} = \sqrt{106} \)
The shortest distance between point 'A' and point 'D' is \(\sqrt{106}\) km.
| Point | Location Relative to Previous Point | Coordinates (assuming O is at (0,0)) |
|---|---|---|
| O | Starting Point | (0, 0) |
| A | 20 km East from O | (20, 0) |
| B | 10 km South from A | (20, -10) |
| C | 9 km West from B | (11, -10) |
| D | 5 km North from C | (11, -5) |
In this problem, we calculated the "shortest distance" between two points, which is essentially the magnitude of the displacement vector between them. This is different from the total distance traveled.
Understanding coordinate geometry is crucial for solving these types of directional distance problems, as it allows you to represent movements in different directions mathematically and use geometric formulas like the distance formula.
In the morning X and Y are walking towards each other in a park. When they meet, Y's shadow' falls upon X. In which direction was X facing?
Two workers K and L start walking from the same point. K walks 5 km North, then turns right and walks 2 km. Meanwhile, L walks 3 km West, then turns South and walks 4 km. Finally L turns left and walks 5 km. Where is K with respect to L?
Sharad starts from Point Y and drives 9 km towards the South. He then takes a left turn, drives 19 km, turns right and drives 23 km. He then takes a right turn and drives 8 km. He takes a right turn and drives 17 km. He then turns left, drives 11 km, turns left and drives 6 km to stop at Point Z. How far (shortest distance) and towards which direction should he drive in order to reach Point Y again? (All turns are 90 degrees turns only unless specified)