The sum of the present ages of two sisters is 67 years. Five years ago from now, the elder sister was twice as old as the younger one. Find the elder sister's current age.
43 years
Let current ages of elder sister = \(E\) and younger sister = \(Y\).
\(E + Y = 67\) ... (1)
\(E - 5 = 2(Y - 5)\) → \(E - 5 = 2Y - 10\) → \(E = 2Y - 5\) ... (2)
Substituting (2) into (1): \((2Y - 5) + Y = 67 \Rightarrow 3Y = 72 \Rightarrow Y = 24\).
Then \(E = 67 - 24 = 43\) years.
The correct answer is : 43 years.
Similar Questions
A person is 5 years older than twice their sibling's age. If the person is currently 27 years old, how old is the sibling?
The difference of the present ages of two friends Gopal and Manoj is 2 years. If the ratio of their ages after 18 years from now will be 21 : 22, then find the sum of their respective ages 10 years ago from now (in years).
A mother's age is double her son's age at present. If the difference of their ages after 24 years from now is 20, then find their ages at present (in years), respectively.
Important Questions from Age
The ratio of the ages of A and B, four years ago, was 4 : 5. Eight years from now, the ratio of the ages of A and B will be 11 : 13. What is the sum of their present ages?
The ratio of the present ages of A and B is 8 : 9. After 9 years, this ratio will become 19 : 21. C is 3 years younger to B. What is the present (in years) of C?
The ratio of the ages of A and B 8 years ago was 2 : 3. Four years ago, the ratio of their ages was 5 : 7. What will be the ratio of their ages 8 years from now?
The ratio of the present age of father to that of his son is 7 : 2. If after 10 years the ratio of their ages will become 9 : 4, then the present age of the father is:
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
