When a parallel beam of light passes through a convex lens, after refraction it:
converges to a point on the principal axis
A convex (converging) lens is thicker at the centre than at the edges. When a parallel beam of light (rays parallel to the principal axis) passes through it, the lens bends all rays inward so that they meet at a single point on the principal axis — the principal focus (F).
This is the defining property of a converging lens: it converges parallel light to the focal point. The image formed at the focal point is real, inverted, and highly diminished (point-sized).
The correct answer is A: converges to a point on the principal axis.
Similar Questions
Which of the following is NOT the correct use of a concave mirror?
The image formed by a concave lens for an object at infinity is:
An object is placed at a distance of 40 cm from a convex lens of focal length 10 cm, such that an image is formed at a distance of X cm from the lens. What is the value of X?
An image is formed at a distance of 30 cm from a convex mirror when the object is placed 40 cm from the mirror. The magnification produced by the mirror will be _______.
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The magnification of a concave mirror is −1. Which of the following statements is correct about the position of the object?
The power of a lens is given as the reciprocal of its:
A ray of light enters a rectangular glass slab from air at an angle of 40 degrees to the normal. If the refractive index of glass with respect to air is 1.5 and the velocity of light in air is \(3 \times 10^{8}\) m/s, what is the velocity of light inside the glass slab?
Important Questions from Refraction and Reflection
A convex lens of focal length f will form a magnified real image of an object, if the object is placed.
A ray of light travelling in the direction \(\frac{1}{2} (\hat i + \sqrt 3 \hat j)\) is incident on a plane mirror. After reflection it travels along the direction \(\frac{1}{2} (\hat i - \sqrt 3 \hat j)\) The angle of incidence is:
Twinkling of stars is due to atmospheric
An optical fibre has a core material of refractive index of 1.55 and cladding material of refractive index of 1.50. The numerical aperture of the fibre is
- The refracting angle of a prism is $A$. The refractive index of the material of the prism is $\frac{1+\cos A}{\sin A}$. The angle of minimum deviation is:
