Points A, B and C lie on a circle with centre O. If ∠ACB = 46.5°, then find the measure of ∠AOB formed on the minor arc AB.
93°
93° is correct.
The angle subtended by an arc at the centre of a circle is twice the angle it subtends at any point on the remaining part of the circle.
Here the minor arc AB subtends \(\angle ACB = 46.5^\circ\) at C on the circle and \(\angle AOB\) at the centre O.
\(\angle AOB = 2 \times \angle ACB = 2 \times 46.5^\circ = 93^\circ\)
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