In the given circle, diameter AB is extended to meet chord CD extended at P. If the lengths of the line segments AP, CP and DP are 12 cm, 8 cm and 6 cm, respectively, what is the length of the radius of the circle?
To solve this problem, we will use the Power of a Point Theorem, which states that for a point P outside a circle, the power of the point is equal to the product of the distances from P to two points on the circle.
In this case, the theorem implies that the product of the whole segment AP and its external segment PB (since AB is a diameter) is equal to the product of CP and DP.
Given:
Using the Power of a Point Theorem, we have: \(AP \times PB = CP \times DP\)
Substituting the known values: \(12 \times PB = 8 \times 6\)
Solving for PB: \(12 \times PB = 48\) \(PB = \frac{48}{12} = 4 \, \text{cm}\)
Since AB is the diameter of the circle, and ∠APB is a right angle (by Thales' theorem), the radius of the circle is half of AB: \(AB = AP - PB = 12 - 4 = 8 \, \text{cm}\)
Therefore, the radius of the circle is: \(\frac{AB}{2} = \frac{8}{2} = 4 \, \text{cm}\)
Thus, the correct answer is 4 cm.
In the given figure, DE is tangent to the circle at a point B. $\Delta \text{ABC}$ is constructed such that A and C are points on the circumference of the given circle, with $\text{AB} = \text{AC}$. If $\angle \text{ABD} = 65^\circ$, then what is $\angle \text{BAC}$? (Figure is not to scale)

There are two concentric circles. The radii of the two circles are 100 m and 110 m respectively. A wheel of radius 30 cm rolls on the smaller circle and another wheel rolls on the larger circle. After they have completed one revolution, it is found that the two wheels rolled equal number of times
on their respective axes. What is the radius of the other wheel ?