Pipe A can fill a tank in 6 hours, pipe B can fill the same tank in 21 hours and pipe C can fill the same tank in 28 hours. The time taken (in hours) by them to fill one-fourth of the same tank if they operate together is:
1
Work done together in one hour = \(\frac{1}{6} + \frac{1}{21} + \frac{1}{28}\) = \(\frac{14 + 4 + 3}{84} = \frac{21}{84} = \frac{1}{4}\) of the tank.
So one-fourth of the tank is filled in 1 hour.
Hence, the answer is 1.
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Important Questions from Pipe and Cistern
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