Pipe A can fill a tank in 6 hours, pipe B can fill the same tank in 28 hours and pipe C can fill the same tank in 21 hours. The time taken (in hours) by them to fill one-fourth of the same tank if they operate together is:
1
Take the capacity of the tank as the LCM of 6, 28 and 21, which is 84 units.
Then pipe A fills 84 ÷ 6 = 14 units per hour, pipe B fills 84 ÷ 28 = 3 units per hour and pipe C fills 84 ÷ 21 = 4 units per hour.
Working together they fill 14 + 3 + 4 = 21 units per hour.
One-fourth of the tank is 84 ÷ 4 = 21 units, which takes 21 ÷ 21 = 1 hour.
Hence, the answer is 1.
One pipe can fill a tank in 6 minutes, while another pipe can empty the completely filled tank in 9 minutes. If both the pipes are opened together when the tank is empty, how many minutes will it take to fill one-half of the tank?
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